Two parallel plates, each having area A = 3548 cm² are connected to the terminals of abattery of voltage V₁ = 6 V as shown. The plates are separated by a distance d = 0.54 cm.1) What is Q, the charge on the top plate?Submit2) What is U, the energy stored in the this capacitor?SubmitSubmit3) The battery is now disconnected from the plates and the separation of the plates is doubled (= 1.08 cm). What is the energy stored in this newcapacitor?4) What is E, the magnitude of the electric field in the region between the plates?Submit25) Compare V, the magnitude of the new potential difference across the plates, to Vb, the voltage of the battery.OV VbSubmitA++N/C+

Given, Area of plates, A=3548cm2A=3548×10-4m2 The battery voltage, Vb=6V Distance,…

Answered: Two parallel plates, each having area A…

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