Two objects are connected by a light string passing over a light, frictionless pulley. The 5.00-kg object isreleased from rest at a point 4.00 m above the floor. Find the speed of the 5.00-kg object when it is 1meter above the floor.m, = 5.00 kgh = 4.00 mm, = 3.00 kg4.756 m/s3.834 m/s4.475 m/s3.942 m/s4.135 m/s3.384 m/sА.D.В.Е.С.F.

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College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

Two objects are connected by a light string passing over a light, frictionless pulley. The 5.00-kg object is
released from rest at a point 4.00 m above the floor. Find the speed of the 5.00-kg object when it is 1
meter above the floor.
m, = 5.00 kg
h = 4.00 m
m, = 3.00 kg
4.756 m/s
3.834 m/s
4.475 m/s
3.942 m/s
4.135 m/s
3.384 m/s
А.
D.
В.
Е.
С.
F.

Expert Solution

Step 1:Introduction

In the pulley system , before the object of mass $m_{1} = 5 k g$ is released from rest , the only energy that exist in the system will be the potential energy of mass $m_{1} = 5 k g$ at height $h_{i} = 4 m$ . When the object is released , this potential energy will be transferred as the kinetic energy of the two masses $m_{1} = 5 k g$ and $m_{2} = 3 k g$ , and the potential energy of the mass $m_{2} = 3 k g$ , when the mass $m_{1} = 5 k g$ reaches the floor as the mass $m_{2} = 3 k g$ will not move anymore at this point.

The potential energy change ,when the mass $m_{1} = 5 k g$ reaches the height $h_{f} = 1 m$ from the height $h_{i} = 4 m$ ,that is height difference of $\begin{array}{rcl} ∆ h & = & h_{f} - h_{i} \\ = & 4 m - 1 m \\ = & 3 m \end{array}$ , will be used by both the masses to reach a velocity of v from initial velocity zero and the potential energy change of mass $m_{2} = 3 k g$ as it reaches an height $h_{2 f} = 3 m$ from floor, that is height difference of $∆ h_{2} = 3 m$ .

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