Answered: A 150 g particle at x = 0 is moving at…

Related questions

Question

A 150 g particle at x = 0 is moving at 2.00 m/s in the +x-direction. As it moves, it experiences a force given by Fx=(0.350N)sin(x/2.00m)Fx=(0.350N)sin⁡(x/2.00m).

What is the particles speed when it reaches x = 3.14 m?

Express your answer with the appropriate units.

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Similar questions

The desperate contestants on a TV survival show are very hungry. The only food they can see is some fruit hanging on a branch high in a tree. Fortunately, they have a spring they can use to launch a rock. The spring constant is 1300 N/m, and they can compress the spring a maximum of 38 cm. All the rocks on the island seem to have a mass of 480 g. With what speed does the rock leave the spring?
A 5.50 ✕ 105 kg subway train is brought to a stop from a speed of 0.500 m/s in 0.300 m by a large spring bumper at the end of its track. What is the force constant k of the spring (in N/m)? N/m A 70.0 kg skier with an initial speed of 10.0 m/s coasts up a 2.50 m high rise as shown in the following figure. Find her final speed at the top (in m/s), given that the coefficient of friction between her skis and the snow is 0.0800. (Hint: Find the distance traveled up the incline assuming a straight-line path as shown in the figure.) m/s
An object whose mass is 10 lb is projected straight upward from the surface of the earth and reaches a height of 100 ft when its velocity reaches zero. The only force acting on the object is the force of gravity. The acceleration of gravity is g = 32.2 ft/s². Determine the initial kinetic energy of the object, in ft·lbf, and the initial velocity of the object, in ft/s.

A 150 g particle at x = 0 is moving at 2.00 m/s in the +x-direction. As it moves, it experiences a force given by Fx=(0.350N)sin(x/2.00m)Fx=(0.350N)sin⁡(x/2.00m). What is the particles speed when it reaches x = 3.14 m

A 150 g particle at x = 0 is moving at 2.00 m/s in the +x-direction. As it moves, it experiences a force given by Fx=(0.350N)sin(x/2.00m)Fx=(0.350N)sin⁡(x/2.00m). What is the particles speed when it reaches x = 3.14 m