A 150 g particle at x = 0 is moving at 2.00 m/s in the +x-direction. As it moves, it experiences a force given by Fx=(0.350N)sin(x/2.00m)Fx=(0.350N)sin⁡(x/2.00m). What is the particles speed when it reaches x = 3.14 m

A 150 g particle at x = 0 is moving at 2.00 m/s in the +x-direction. As it moves, it experiences a force given by Fx=(0.350N)sin(x/2.00m)Fx=(0.350N)sin⁡(x/2.00m). What is the particles speed when it reaches x = 3.14 m

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Question

A 150 g particle at x = 0 is moving at 2.00 m/s in the +x-direction. As it moves, it experiences a force given by Fx=(0.350N)sin(x/2.00m)Fx=(0.350N)sin⁡(x/2.00m).

What is the particles speed when it reaches x = 3.14 m?

Express your answer with the appropriate units.

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