Jane, looking for Tarzan, is running at a speed (6.40 m/s) and grabs a ne hanging vertically from a tall tree in the jungle. How high can she ving upward?(g = 9.8 m/s²)

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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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### Physics Problem: Swinging on a Vine

**Problem Statement:**

Jane, looking for Tarzan, is running at a speed of 6.40 m/s and grabs a vine hanging vertically from a tall tree in the jungle. How high can she swing upward? \((g = 9.8 \, m/s^2)\)

[Input Box]
__________ meters

**Detailed Explanation:**

1. **Given Data:**
   - Initial speed (v_i): 6.40 m/s
   - Acceleration due to gravity (g): 9.8 m/s²

2. **Concept Applied:**
   - The problem involves the conversion of kinetic energy to potential energy.

3. **Formulas:**
   - Kinetic Energy (K.E): \( \frac{1}{2}mv_i^2 \)
   - Potential Energy (P.E): \( mgh \)
   - At the highest point, all kinetic energy will convert into potential energy:
     \[ \frac{1}{2}mv_i^2 = mgh \]

4. **Solving for Height (h):**
   \[ h = \frac{v_i^2}{2g} \]

   Substituting the given values:
   \[ h = \frac{(6.40 \, m/s)^2}{2 \times 9.8 \, m/s^2} \]
   \[ h = \frac{40.96}{19.6} \]
   \[ h \approx 2.09 \, meters \]

So, the height \( h \) that Jane can swing upward is approximately 2.09 meters.

**Reminder:** This calculation assumes no energy loss due to air resistance or friction.
Transcribed Image Text:### Physics Problem: Swinging on a Vine **Problem Statement:** Jane, looking for Tarzan, is running at a speed of 6.40 m/s and grabs a vine hanging vertically from a tall tree in the jungle. How high can she swing upward? \((g = 9.8 \, m/s^2)\) [Input Box] __________ meters **Detailed Explanation:** 1. **Given Data:** - Initial speed (v_i): 6.40 m/s - Acceleration due to gravity (g): 9.8 m/s² 2. **Concept Applied:** - The problem involves the conversion of kinetic energy to potential energy. 3. **Formulas:** - Kinetic Energy (K.E): \( \frac{1}{2}mv_i^2 \) - Potential Energy (P.E): \( mgh \) - At the highest point, all kinetic energy will convert into potential energy: \[ \frac{1}{2}mv_i^2 = mgh \] 4. **Solving for Height (h):** \[ h = \frac{v_i^2}{2g} \] Substituting the given values: \[ h = \frac{(6.40 \, m/s)^2}{2 \times 9.8 \, m/s^2} \] \[ h = \frac{40.96}{19.6} \] \[ h \approx 2.09 \, meters \] So, the height \( h \) that Jane can swing upward is approximately 2.09 meters. **Reminder:** This calculation assumes no energy loss due to air resistance or friction.
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