Two nitro (NO,) groups are chemically bonded to a patch of surface. They can't move to another location on the surface, but theycan rotate (see sketch at right).It turns out that the amount of rotational kinetic energy each NO, group can have is required to be a multiple of ɛ, where8= 1.0 x 10-24J. In other words, each NO, group could have ɛ of rotational kinetic energy, or 2ɛ, or 3ɛ, and so forth - but itcannot have just any old amount of rotational kinetic energy.Two rotating N0, groupsSuppose the total rotational kinetic energy in this system is initially known to be 41ɛ. Then, some heat is removed from thebonded to a surface.system, and the total rotational kinetic energy falls to 30ɛ. Calculate the change in entropy.Round your answer to 3 significant digits, and be sure it has the correct unit symbol.Check2021 McGraw-Hill Education All Rights Reserved Tems of Uhe Privacy AccesbilExplanationMacBook Airolo

Given data: Rotational kinetic energy Er1=41ε Rotational kinetic energy Er1=30ε…

Two nitro (N0,) groups are chemically bonded to a patch of surface. They can't move to another location on the surface, but they can rotate (see sketch at right). It turns out that the amount of rotational kinetic energy each NO, group can have is required to be a multiple of ɛ, where 8=1.0 x 10 -24 J. In other words, each NO, group could have ɛ of rotational kinetic energy, or 2ɛ, or 3ɛ, and so forth – but it cannot have just any old amount of rotational kinetic energy. Two rotating NO, groups Suppose the total rotational kinetic energy in this system is initially known to be 41ɛ. Then, some heat is removed from the bonded to a surface. system, and the total rotational kinetic energy falls to 30ɛ. Calculate the change in entropy. Round your answer to 3 significant digits, and be sure it has the correct unit symbol.

Two nitro (N0,) groups are chemically bonded to a patch of surface. They can't move to another location on the surface, but they can rotate (see sketch at right). It turns out that the amount of rotational kinetic energy each NO, group can have is required to be a multiple of ɛ, where 8=1.0 x 10 -24 J. In other words, each NO, group could have ɛ of rotational kinetic energy, or 2ɛ, or 3ɛ, and so forth – but it cannot have just any old amount of rotational kinetic energy. Two rotating NO, groups Suppose the total rotational kinetic energy in this system is initially known to be 41ɛ. Then, some heat is removed from the bonded to a surface. system, and the total rotational kinetic energy falls to 30ɛ. Calculate the change in entropy. Round your answer to 3 significant digits, and be sure it has the correct unit symbol.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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