Determine AH° for the reaction CS2(1) + 3C12 (g)→CCL (1) + S2Cl2 (1). Use appropriate data from the following listing. CS2(1) + 302(g)→CO2(g) + 2SO2(g), AH° = -1077 kJ/mol 25(s) + C2 (g)S,Ch(1), AH° = -58.2 kJ/mol C(s) + 2Cl2 (g)→CCL4 (1), AH° = - -135.4 kJ/mol S(s) + O2(g)SO2(g). AH° = -296.8 kJ/mol SO- (g) + C2 (g)¬SO,Ch(1), AH° = +97.3 kJ/mol C(s) + O2 (g) CO2 (g), AH° = -393.5 kJ/mol CCI (1) + O2(g)→COCH (g) + Ch0(g), AH° = -5.2 kJ/mol ΔΗ' kJ/mol
Determine AH° for the reaction CS2(1) + 3C12 (g)→CCL (1) + S2Cl2 (1). Use appropriate data from the following listing. CS2(1) + 302(g)→CO2(g) + 2SO2(g), AH° = -1077 kJ/mol 25(s) + C2 (g)S,Ch(1), AH° = -58.2 kJ/mol C(s) + 2Cl2 (g)→CCL4 (1), AH° = - -135.4 kJ/mol S(s) + O2(g)SO2(g). AH° = -296.8 kJ/mol SO- (g) + C2 (g)¬SO,Ch(1), AH° = +97.3 kJ/mol C(s) + O2 (g) CO2 (g), AH° = -393.5 kJ/mol CCI (1) + O2(g)→COCH (g) + Ch0(g), AH° = -5.2 kJ/mol ΔΗ' kJ/mol
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
CCl4,an important commercial solvent,is prepared by the reaction of Cl2(g)with a carbon compound. Determine the ∆Ho for the reaction
CS2(l) + 3 Cl2(g) → CCl4(l) + S2Cl2(l)
![Part A
Determine AH° for the reaction
CS2 (1) + 3C12 (g)→CCL (1) + S2 Cl2 (1).
Use appropriate data from the following listing.
CS2 (1) + 302 (g)→CO2 (g) + 2SO2 (g), AH° = -1077 kJ/mol
25(s) + Cl2 (g)→S, Cl2 (1), AH°
= -58.2 kJ/mol
C(s) + 2Cl2 (g)→CC4 (1), AH° = -135.4 kJ/mol
S(s) + 02 (g)-S02 (g), AH° = -296.8 kJ/mol
SO (g) + Cl2 (g)–→SO2C (1), AH° = +97.3 kJ/mol
C(s) + 02 (g)-CO2 (g), AH° = -393.5 kJ/mol
CCI4 (1) + O2 (g)→COC2 (g) + Cl20(g), AH°
= -5.2 kJ/mol
?
AH° =
kJ/mol
Submit
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Transcribed Image Text:Part A
Determine AH° for the reaction
CS2 (1) + 3C12 (g)→CCL (1) + S2 Cl2 (1).
Use appropriate data from the following listing.
CS2 (1) + 302 (g)→CO2 (g) + 2SO2 (g), AH° = -1077 kJ/mol
25(s) + Cl2 (g)→S, Cl2 (1), AH°
= -58.2 kJ/mol
C(s) + 2Cl2 (g)→CC4 (1), AH° = -135.4 kJ/mol
S(s) + 02 (g)-S02 (g), AH° = -296.8 kJ/mol
SO (g) + Cl2 (g)–→SO2C (1), AH° = +97.3 kJ/mol
C(s) + 02 (g)-CO2 (g), AH° = -393.5 kJ/mol
CCI4 (1) + O2 (g)→COC2 (g) + Cl20(g), AH°
= -5.2 kJ/mol
?
AH° =
kJ/mol
Submit
Request Answer
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