Two negative charges, each with a charge of -7.7 nC, are at fixed locations as shown below.A proton is launched from the midpoint of the line joining the charges in a directionperpendicular to the line joining the charges. Find the minimum initial velocity of the protonthat will allow it to escape to infinity. Ignore gravitational or any other influences on theproton.(k=1/480 = 8.99 × 109 Nm²/C2, e = 1.60 × 10-19 C, mproton = 1.67× 10-27 kg). [Hint:Conservation of energy might be helpful and you can assume that the proton is at rest atinfinity]5.0 mm5.0 mmV8.9 × 106 m/s1.8 × 107 m/sNone of these4.6 × 106 m/s2.3 × 106 m/s

Given: The magnitude of the negative charge is 7.7 nC or 7.7×10-9 C The distance between…

Answered: Two negative charges, each with a…

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