A 1.96  10-9 C charge has coordinates x = 0, y = −2.00; a 2.76  10-9 C charge has coordinates x = 3.00, y = 0; and a -5.25  10-9 C charge has coordinates x = 3.00, y = 4.00, where all distances are in cm. Determine magnitude and direction for the electric field at the origin and the instantaneous acceleration of a proton placed at the origin. (a) Determine the magnitude and direction for the electric field at the origin (measure the angle counterclockwise from the positive x-axis). (b) Determine the magnitude and direction for the instantaneous acceleration of a proton placed at the origin (measure the angle counterclockwise from the positive x-axis).

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A 1.96  10-9 C charge has coordinates x = 0, y = −2.00; a 2.76  10-9 C charge has coordinates x = 3.00, y = 0; and a -5.25  10-9 C charge has coordinates x = 3.00, y = 4.00, where all distances are in cm. Determine magnitude and direction for the electric field at the origin and the instantaneous acceleration of a proton placed at the origin.

(a) Determine the magnitude and direction for the electric field at the origin (measure the angle counterclockwise from the positive x-axis).
(b) Determine the magnitude and direction for the instantaneous acceleration of a proton placed at the origin (measure the angle counterclockwise from the positive x-axis).
Expert Solution
Step 1

Given,

Charges are,

QA=1.96×10-9CQB=-2.00×10-9CQC=-5.25×10-9C

And coordinates of charges are

QA0, -2cm         QB3cm, 0        QC3cm, 4cm

So position vectors are,

rA=-2×10-2j^mrB=3×10-2i^mrC=3×10-2i^+4×10-2j^m

Since the electric field at point O is

E=kqr2r^=kqr3r

where k is coulomb's constant, r is the radial vector from charge to point O and q is the charge.

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