• Two long, parallel wires separated by 0.20 m car qual currents of 1.5 A in the same direction. Find th nagnitude and direction of the magnetic field 0.15 r

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Chapter1: Units, Trigonometry. And Vectors
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I need help solving this problem. If you could explain using the right hand rule that would be great. 

 

39. • Two long, parallel wires separated by 0.20 m carry
equal currents of 1.5 A in the same direction. Find the
magnitude and direction of the magnetic field 0.15 m
away from each wire on the side opposite the other wire
Transcribed Image Text:39. • Two long, parallel wires separated by 0.20 m carry equal currents of 1.5 A in the same direction. Find the magnitude and direction of the magnetic field 0.15 m away from each wire on the side opposite the other wire
0.20 m!!
1-1.5 А
I = 1.5 A
B = ?
B = ?
0.15 m
0.15 m
Transcribed Image Text:0.20 m!! 1-1.5 А I = 1.5 A B = ? B = ? 0.15 m 0.15 m
Expert Solution
Step 1

Let the two long, parallel wires separated by d =  0.20 m carry an equal current of I = 1.5 A in the same direction.

The magnetic field at a distance a = 1.5 m away from each wire 

So now 

We  know that the formula of the magnetic field is given as 

B = μ0I2πr

where μ0  is the permeability  of the free space 

I is the current 

r is the distance at which the magnetic field is B 

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