The vector torque is デーデ×F where " is the vector from the axis of rotation to where the force is applied. Tis Which is the direction of the torque vector? +y 7 (in) +z (out) = in = out

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+z
+X
-z
+y
O -y
O In the x-y plane at 315° ccw from +x
-X
In the x-y plane at 225° ccw from +x
O In the x-y plane at 45° ccw from +x
O In the x-y plane at 135° ccw from +x
Transcribed Image Text:+z +X -z +y O -y O In the x-y plane at 315° ccw from +x -X In the x-y plane at 225° ccw from +x O In the x-y plane at 45° ccw from +x O In the x-y plane at 135° ccw from +x
The cross product
AxB
is perpendicular to both vectors in the cross product (think of Aand
В
as lying on a
sheet of paper; the cross product is perpendicular to the plane of the sheet).
After figuring out the two directions perpendicular to both vectors you use one of the right hand rules given
on Page 338 to choose which of the two direction is correct. All three should give the same result so use
whichever one you are most comfortable with. In class, we will use the middle one in the diagram in the book.
The vector torque is
where "is the vector from the axis of rotation to where the force is applied.
Which is the direction of the torque vector?
+y
++
* (in)
+z (out)
O = in
(O) = out
Transcribed Image Text:The cross product AxB is perpendicular to both vectors in the cross product (think of Aand В as lying on a sheet of paper; the cross product is perpendicular to the plane of the sheet). After figuring out the two directions perpendicular to both vectors you use one of the right hand rules given on Page 338 to choose which of the two direction is correct. All three should give the same result so use whichever one you are most comfortable with. In class, we will use the middle one in the diagram in the book. The vector torque is where "is the vector from the axis of rotation to where the force is applied. Which is the direction of the torque vector? +y ++ * (in) +z (out) O = in (O) = out
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