Two independent samples have been selected, 70 observations from population 1 and 74 observations from population 2.The sample means have been calculated to be x1 = 14.2 and x2 = 14.7. From previous experience with these populations, it isknown that the variances are o = 22 and o,= 40.(a) Find o (71-T2)·answer:(b) Determine the rejection region for the test of H, : (µ1 – µ2) = 2.29 and H. : (µ1 – µ2) > 2.29 Use a = 0.03.z >(c) Compute the standardized test statistic.2 =The final conclustion isO A. We can reject the null hypothesis that (u - Hz) = 2.29 and accept that (uj - l2) > 2.29.O B. There is not sufficient evidence to reject the null hypothesis that (u1 – µ2) = 2.29.(d) Construct a 97 % confidence interval for (u1 - 42).< (41 - H2) <

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Description: Two independent samples have been selected, 70 observations from population 1 and 74 observations from population 2.The sample means have been calculated to be x1 = 14.2 and x2 = 14.7. From previous experience with these populations, it isknown that

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Two independent samples have been selected, 70 observations from population 1 and 74 observations from population 2. = 14.7. From previous experience with these populations, it is = 14.2 and a2 The sample means have been calculated to be known that the variances are o = 22 and o, = 40. (a) Find o (71-72). answer: (b) Determine the rejection region for the test of Ho : (µ1 – µ2) = 2.29 and H. : (µ1 - 42) > 2.29 Use a = 0.03. (c) Compute the standardized test statistic. The final conclustion is = 2.29 and accept that (µ1 – µ2) > 2.29. O A. We can reject the null hypothesis that (u1 – Hz) O B. There is not sufficient evidence to reject the null hypothesis that (µ1 – µ2) = 2.29. - (d) Construct a 97 % confidence interval for (µ1 – µ2). < (H1 – H2) <

Two independent samples have been selected, 70 observations from population 1 and 74 observations from population 2. = 14.7. From previous experience with these populations, it is = 14.2 and a2 The sample means have been calculated to be known that the variances are o = 22 and o, = 40. (a) Find o (71-72). answer: (b) Determine the rejection region for the test of Ho : (µ1 – µ2) = 2.29 and H. : (µ1 - 42) > 2.29 Use a = 0.03. (c) Compute the standardized test statistic. The final conclustion is = 2.29 and accept that (µ1 – µ2) > 2.29. O A. We can reject the null hypothesis that (u1 – Hz) O B. There is not sufficient evidence to reject the null hypothesis that (µ1 – µ2) = 2.29. - (d) Construct a 97 % confidence interval for (µ1 – µ2). < (H1 – H2) <

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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