Two independent groups of students were selected to participate in a study to determine if having video lectures in an online class has an effect on test scores. The students were randomly (SRS) placed into 2 groups, one group was the online class of 30 students with video lectures and the other group was the online class of 33 students without video lectures. The average test score on the online class of 30 students with video lectures was x-bar:  87 with a standard deviation of s = 1.8 and the average test score the online class of 33 students without video lectures x-bar = 86 with a standard deviation of s = 3.2. Is there enough evidence at the 1% level that the test scores of the online class with video lectures are higher than the test scores of the online class without video lectures? What is set up work for this problem?: a) x-bar1 = 87, s1 = 1.8, n1 = 30, x-bar2 = 86, s2 = 3.2, n2 = 33, SE = 0.6468, z score = (87-86)/0.6468 = 1.55, p-value = 0.128 b) x-bar1 = 87, s1 = 1.8, n1 = 30, x-bar2 = 86, s2 = 3.2, n2 = 33, SE = 0.6468, z score = (86-87)/0.6468 = -1.55, p-value = 0.936 c) x-bar1 = 87, s1 = 1.8, n1 = 30, x-bar2 = 86, s2 = 3.2, n2 = 33, SE = 0.6468, z score = (87-86)/0.6468 = 1.55, p-value = 0.064 d) x-bar1 = 87, s1 = 1.8, n1 = 30, x-bar2 = 86, s2 = 3.2, n2 = 33, SE = 0.3962, z score = (87-86)/0.3962 = 2.52, p-value = 0.0059

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
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ISBN:9780079039897
Author:Carter
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Chapter10: Statistics
Section10.3: Measures Of Spread
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Two independent groups of students were selected to participate in a study to determine if having video lectures in an online class has an effect on test scores. The students were randomly (SRS) placed into 2 groups, one group was the online class of 30 students with video lectures and the other group was the online class of 33 students without video lectures. The average test score on the online class of 30 students with video lectures was x-bar:  87 with a standard deviation of s = 1.8 and the average test score the online class of 33 students without video lectures x-bar = 86 with a standard deviation of s = 3.2. Is there enough evidence at the 1% level that the test scores of the online class with video lectures are higher than the test scores of the online class without video lectures? What is set up work for this problem?:

a) x-bar1 = 87, s1 = 1.8, n1 = 30, x-bar2 = 86, s2 = 3.2, n2 = 33, SE = 0.6468, z score = (87-86)/0.6468 = 1.55, p-value = 0.128

b) x-bar1 = 87, s1 = 1.8, n1 = 30, x-bar2 = 86, s2 = 3.2, n2 = 33, SE = 0.6468, z score = (86-87)/0.6468 = -1.55, p-value = 0.936

c) x-bar1 = 87, s1 = 1.8, n1 = 30, x-bar2 = 86, s2 = 3.2, n2 = 33, SE = 0.6468, z score = (87-86)/0.6468 = 1.55, p-value = 0.064

d) x-bar1 = 87, s1 = 1.8, n1 = 30, x-bar2 = 86, s2 = 3.2, n2 = 33, SE = 0.3962, z score = (87-86)/0.3962 = 2.52, p-value = 0.0059

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