Two identical tiny balls of highly compressed matter are 1.50 apart. When released in an orbiting space station, they accelerate toward each other at 2.00 cm/s². (G= 6.67 x 10-11 N-m²/kg²) What is the mass of each of them? x 10 kg

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### Physics Problem: Gravitational Attraction of Compressed Matter Balls

**Problem Statement:**
Two identical tiny balls of highly compressed matter are 1.50 meters apart. When released in an orbiting space station, they accelerate toward each other at 2.00 cm/s². 

Given:
- Separation distance (\( d \)): 1.50 m
- Acceleration (\( a \)): 2.00 cm/s² \( = 0.02 \) m/s²
- Gravitational constant (\( G \)): \( 6.67 \times 10^{-11} \) N \( \cdot \) m²/kg²

**Question:**
What is the mass of each of them?

**Equation for gravitational force:**
\[ F = G \frac{m_1 m_2}{d^2} \]
Where:
- \( F \) is the gravitational force,
- \( G \) is the gravitational constant,
- \( m_1 \) and \( m_2 \) are the masses of the balls,
- \( d \) is the separation distance.

Since the balls are identical, \( m_1 = m_2 = m \). Additionally, using Newton's second law of motion (\( F = ma \)), and substituting into the gravitational force equation, we get:
\[ m \cdot a = G \frac{m^2}{d^2} \]
\[ a = G \frac{m}{d^2} \]
\[ m = \frac{a d^2}{G} \]

**Calculation:**
Plugging in the values:
\[ m = \frac{0.02 \cdot (1.50)^2}{6.67 \times 10^{-11}} \]
\[ m = \frac{0.02 \cdot 2.25}{6.67 \times 10^{-11}} \]
\[ m = \frac{0.045}{6.67 \times 10^{-11}} \]
\[ m \approx 6.75 \times 10^{8} \text{ kg} \]

**Answer:**
The mass of each ball is:
\[ 6.75 \times 10^{8} \text{ kg} \]
Transcribed Image Text:### Physics Problem: Gravitational Attraction of Compressed Matter Balls **Problem Statement:** Two identical tiny balls of highly compressed matter are 1.50 meters apart. When released in an orbiting space station, they accelerate toward each other at 2.00 cm/s². Given: - Separation distance (\( d \)): 1.50 m - Acceleration (\( a \)): 2.00 cm/s² \( = 0.02 \) m/s² - Gravitational constant (\( G \)): \( 6.67 \times 10^{-11} \) N \( \cdot \) m²/kg² **Question:** What is the mass of each of them? **Equation for gravitational force:** \[ F = G \frac{m_1 m_2}{d^2} \] Where: - \( F \) is the gravitational force, - \( G \) is the gravitational constant, - \( m_1 \) and \( m_2 \) are the masses of the balls, - \( d \) is the separation distance. Since the balls are identical, \( m_1 = m_2 = m \). Additionally, using Newton's second law of motion (\( F = ma \)), and substituting into the gravitational force equation, we get: \[ m \cdot a = G \frac{m^2}{d^2} \] \[ a = G \frac{m}{d^2} \] \[ m = \frac{a d^2}{G} \] **Calculation:** Plugging in the values: \[ m = \frac{0.02 \cdot (1.50)^2}{6.67 \times 10^{-11}} \] \[ m = \frac{0.02 \cdot 2.25}{6.67 \times 10^{-11}} \] \[ m = \frac{0.045}{6.67 \times 10^{-11}} \] \[ m \approx 6.75 \times 10^{8} \text{ kg} \] **Answer:** The mass of each ball is: \[ 6.75 \times 10^{8} \text{ kg} \]
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