Two identical parallel-plate capacitors, each with capacitance 20.0 ?F, are charged to potential difference 50.5 V and then disconnected from the battery. They are then connected to each other in parallel with plates of like sign connected. Finally, the plate separation in one of the capacitors is doubled.(a) Find the total energy of the system of two capacitors before the plate separation is doubled.(b) Find the potential difference across each capacitor after the plate separation is doubled.(c) Find the total energy of the system after the plate separation is doubled.(d) Reconcile the difference in the answers to parts (a) and (c) with the law of conservation of energy. Note: See image for the original question. Two identical parallel-plate capacitors, each with capacitance 20.0 µF, are charged to potential difference 50.5 V and then disconnected from the battery. They are then connected to each other inparallel with plates of like sign connected. Finally, the plate separation in one of the capacitors is doubled.(a) Find the total energy of the system of two capacitors before the plate separation is doubled.(b) Find the potential difference across each capacitor after the plate separation is doubled.V(c) Find the total energy of the system after the plate separation is doubled.(d) Reconcile the difference in the answers to parts (a) and (c) with the law of conservation of energy.Positive work is done by the agent pulling the plates apart.Negative work is done by the agent pulling the plates apart.O No work is done by pulling the agent pulling the plates apart.

Given that: Both the capacitors are identical and parallel plate capacitors Capacitance, C=20μF…

Answered: Two identical parallel-plate…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Two identical parallel-plate capacitors, each with capacitance 20.0 ?F, are charged to potential difference 50.5 V and then disconnected from the battery. They are then connected to each other in parallel with plates of like sign connected. Finally, the plate separation in one of the capacitors is doubled.

(a) Find the total energy of the system of two capacitors before the plate separation is doubled.

(b) Find the potential difference across each capacitor after the plate separation is doubled.

(d) Reconcile the difference in the answers to parts (a) and (c) with the law of conservation of energy.

Note: See image for the original question.

Two identical parallel-plate capacitors, each with capacitance 20.0 µF, are charged to potential difference 50.5 V and then disconnected from the battery. They are then connected to each other in
parallel with plates of like sign connected. Finally, the plate separation in one of the capacitors is doubled.
(a) Find the total energy of the system of two capacitors before the plate separation is doubled.
(b) Find the potential difference across each capacitor after the plate separation is doubled.
V
(c) Find the total energy of the system after the plate separation is doubled.
(d) Reconcile the difference in the answers to parts (a) and (c) with the law of conservation of energy.
Positive work is done by the agent pulling the plates apart.
Negative work is done by the agent pulling the plates apart.
O No work is done by pulling the agent pulling the plates apart.

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