A parallel-plate capacitor has plates of area 0.11 m2 and a separation of 1.1 cm. A battery charges the plates to a potential difference of 130 V and is then disconnected. A dielectric slab of thickness 3.7 mm and dielectric constant 9.0 is then placed symmetrically between the plates. (a) What is the capacitance before the slab is inserted? (b) What is the capacitance with the slab in place? What is the free charge q (c) before and (d) after the slab is inserted? What is the magnitude of the electric field (e) in the space between the plates and dielectric and (f) in the dielectric itself? (g) With the slab in place, what is the potential difference across the plates? (h) How much external work is involved in inserting the slab? (a) Number i Units (b) Number i Units (c) Number Units (d) Number Units

A parallel-plate capacitor has plates of area 0.11 m2 and a separation of 1.1 cm. A battery charges the plates to a potential difference of 130 V and is then disconnected. A dielectric slab of thickness 3.7 mm and dielectric constant 9.0 is then placed symmetrically between the plates. (a) What is the capacitance before the slab is inserted? (b) What is the capacitance with the slab in place? What is the free charge q (c) before and (d) after the slab is inserted? What is the magnitude of the electric field (e) in the space between the plates and dielectric and (f) in the dielectric itself? (g) With the slab in place, what is the potential difference across the plates? (h) How much external work is involved in inserting the slab? (a) Number i Units (b) Number i Units (c) Number Units (d) Number Units

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

A parallel plate capacitor that has C0 capacitance is fully charged by means of of a battery, which is immediately removed. The ddp between the capacitor plates is V0. A dielectric blade with dielectric constant K is then inserted between the capacitor plates. Describe qualitatively the that happens with electric charge, capacitance, potential difference and electric field.
The capacitance of an empty capacitor is 1.2 μF. The capacitor is connected to a 12-V battery and charged up. With the capacitor connected to the battery, a slab of dielectric material is inserted between the plates. As a result, 2.6 × 10–5 C of additional charge flows from one plate, through the battery, and onto the other plate. What is the dielectric constant of the material?
An engineer working in an electronics lab connects a parallel-plate capacitor to a battery, so that the potential difference between the plates is 230 V. Assume a plate separation of d = 1.38 cm and a plate area of A - 25.0 cm. When the battery is removed, the capacitor is plunged into a container of distilled water. Assume distilled water is an insulator with a dielectric constant of 80.0. d into (a) Calculate the charge on the plates (in pC) before and after the capacitor is submerged. (Enter the magnitudes.) O - 369 Q, = 369 before V pc after v pC (b) Determine the capacitance (in F) and potential difference (in V) after immersion. C, - 128 You will naed to include a dielectric constant when you calculate the final capacitance. Nota that x= 80 for distillad water. F AV, = (c) Determine the change in energy (in n)) of the capacitor. Au: (d) what If? Repeat parts (a) through (c) of the problem in the case that the capacitor is immersed in distilled water while still connected to the…
A certain capacitor has a capacitance of 4μF when its plates are separated by 0.2 mm of vacant space. A battery is used to charge the plate to a potential difference of 500 V and is then disconnected from the system. (a) What will be the potential difference across the plates if a sheet of mica 0.2 mm thick is inserted between the plates? (b) What will the capacitance be after the dielectric is inserted? (c) What is the permittivity of mica?
A parallel plate capacitor consists of two rectangular plates, each with an area of 4.5 cm? and separated from each other by a 2.00 mm thick dielectric with a dielectric constant of 5.26. The capacitor is connected to a 12V battery. How much energy is stored in the capacitor.
A capacitor is made of 2 rectangular metal plates with side length of 3cmx6cm separated by a distance of 2.36cm with water in between the plates. The capacitor has a voltage of 110v and is not connected to a battery. (a.) Calculate the capacitance. (b.) What is the new capacitance if we replace water with a new dielectric material with a constant of 3.75 in between the plates? (c.) What is the new voltage? (d.) What is the charge on each plate?
A Capacitor (w/out a dielectric) is connected to a 3V battery and is charged by an amount of 9.7x10^-6 C. A dielectric (w/ K=83) is then inserted between its plates. What is the new capacitance of this capacitor in F?
In a parallel-plate capacitor, the two plates each have an area of 0.460 m2 and are spaced 3.00 mm apart.The capacitor is charged to a voltage of 4.00 kV using a power source that is then removed. The gap between the plates is then filled by a dielectric layer. The charge on each plate stays constant at 2.50 kV despite the reduction in the potential difference between the plates.Calculate the initial capacitance value of the system.
A parallel plate, air filled capacitor, has plates of area 0.61 m2 and a separation of 0.1 mm.What is its capacitance? (Units: nF=10-9F)
A capacitor is made with plates of area A = 0.255 m2, separated by a distance d = 0.386 mm. Between the plates is a layer of a material with dielectric constant κ = 2.15. What is the capacitance of the capacitor? Your answer should be in nano-farads (nF)
a certain capacitor has a capacitance of 4 uf when its plates are separated by 0.2 mm of vacant space.A battery is used to charge the plate to a potential difference of 500 V and is then disconnected from the system. assume that the source of voltage remains connected to the 4 uf capacitor. what will be the increase in charge as a result of the insertion of the sheet of mica?
The capacitance of an empty capacitor is 1.2 μF. The capacitor is connected to a 12-V battery and charged up. With the capacitor connected to the battery, a slab of dielectric material is inserted between the plates. As a result, 2.6 × 10–5 C of additional charge flows from one plate, through the battery, and onto the other plate. What is the dielectric constant of the material?