The capacitor is charged to a voltage of 4.00 kV using a power source that is then removed. The gap between the plates is then filled by a dielectric layer. The charge on each plate stays constant at 2.50 kV despite the reduction in the potential difference between the plates. Calculate the initial capacitance value of the system.
The capacitor is charged to a voltage of 4.00 kV using a power source that is then removed. The gap between the plates is then filled by a dielectric layer. The charge on each plate stays constant at 2.50 kV despite the reduction in the potential difference between the plates. Calculate the initial capacitance value of the system.
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Transcribed Image Text:The capacitor is charged to a
voltage of 4.00 kv using a
power source that is then
removed. The gap between the
plates is then filled by a
dielectric layer. The charge on
each plate stays constant at
2.50 kv despite the reduction
in the potential difference
between the plates.
Calculate the initial
capacitance value of the
system.
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