Two forces equal in magnitude and opposite in direction, acting on an object at two different points, form what is called a couple. Two antiparallel forces with equal magnitudes F₁ F2 = 6.40 N are applied to a rod as shown in the figure (Figure 1). For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of locating your Figure 0 < F₂ 3.00 m →→→→ 1 of 1 > ▼ Part A What should the distance between the forces be if they are to provide a net torque of 5.60 Nm about the left end of the rod? Express your answer in meters. 1= Submit {— ΑΣΦ S Request Answer a ? Review | Constants m

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**Question:** What should the distance \( l \) between the forces be if they are to provide a net torque of 5.60 N \cdot m about the point on the rod where \( \vec{F}_2 \) is applied?

**Instruction:** Express your answer in meters.

**Answer Box:** There is an input box labeled with "l" for users to enter the distance in meters. There are buttons for additional functions like mathematical symbols and operations.

**Note:** No graphs or diagrams are present in the image.
Transcribed Image Text:**Question:** What should the distance \( l \) between the forces be if they are to provide a net torque of 5.60 N \cdot m about the point on the rod where \( \vec{F}_2 \) is applied? **Instruction:** Express your answer in meters. **Answer Box:** There is an input box labeled with "l" for users to enter the distance in meters. There are buttons for additional functions like mathematical symbols and operations. **Note:** No graphs or diagrams are present in the image.
### Understanding Torque and Couples in Physics

**Concept Overview:**

Two forces equal in magnitude and opposite in direction, acting on an object at two different points, constitute what is known as a *couple*. In this scenario, two antiparallel forces labeled \( F_1 = F_2 = 6.40 \, \text{N} \) are applied to a rod.

**Problem Statement:**

**Part A:**  
Determine what the distance \( l \) between the forces should be, so they provide a net torque of \( 5.60 \, \text{N} \cdot \text{m} \) about the left end of the rod. Please provide your answer in meters.

**Diagram Explanation:**

- A horizontal rod is depicted, marked as \( O \) on the left end, with a total length with a gap of \( 3.00 \, \text{m} \) up to the point where \( F_1 \) is applied.
- The force \( F_1 \) acts upwards, while \( F_2 \) acts downwards, both indicated by arrows.
- \( l \) is displayed as the distance between the points of application of the forces \( F_1 \) and \( F_2 \).

To calculate \( l \), you can use the formula for torque from a couple:  
\[ \text{Torque} = F \times l \]

Substitute the known values into the equation to solve for \( l \).

➡️ **Submit your answer using the response box provided.**
Transcribed Image Text:### Understanding Torque and Couples in Physics **Concept Overview:** Two forces equal in magnitude and opposite in direction, acting on an object at two different points, constitute what is known as a *couple*. In this scenario, two antiparallel forces labeled \( F_1 = F_2 = 6.40 \, \text{N} \) are applied to a rod. **Problem Statement:** **Part A:** Determine what the distance \( l \) between the forces should be, so they provide a net torque of \( 5.60 \, \text{N} \cdot \text{m} \) about the left end of the rod. Please provide your answer in meters. **Diagram Explanation:** - A horizontal rod is depicted, marked as \( O \) on the left end, with a total length with a gap of \( 3.00 \, \text{m} \) up to the point where \( F_1 \) is applied. - The force \( F_1 \) acts upwards, while \( F_2 \) acts downwards, both indicated by arrows. - \( l \) is displayed as the distance between the points of application of the forces \( F_1 \) and \( F_2 \). To calculate \( l \), you can use the formula for torque from a couple: \[ \text{Torque} = F \times l \] Substitute the known values into the equation to solve for \( l \). ➡️ **Submit your answer using the response box provided.**
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