You are working in an ice skating rink and have been asked to hang a new banner on the wall. Your friend is helping you so that the ladder does not collapse by exerting a force F→AL at an angle phi relative to the horizontal. See the diagram below. The ladder has a length L and makes an angle of theta with respect to the vertical wall. You have a mass, m_Y, and are a horizontal distance x from the wall. The ladder has a mass of m_L. Because the wall is slick, and the ice on the floor is slick, the frictional forces acting on the ladder are negligible. Part One: Find a formula for the magnitude of the force that your friend must exert to keep the ladder from falling, in terms of the following variables: x,L,m_Y,m_L,theta,phi. Then use the following values to get a number for the magnitude of F→AL. theta = 29.5 degrees phi = 23.305 degrees x= 2.204 meters L = 7.6 meters m_Y= 82 kg m_L = 34.44kg

College Physics
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Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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You are working in an ice skating rink and have been asked to hang a new banner on the wall. Your friend is helping you so that the ladder does not collapse by exerting a force F→AL at an angle phi relative to the horizontal. See the diagram below.

The ladder has a length L and makes an angle of theta with respect to the vertical wall. You have a mass, m_Y, and are a horizontal distance x from the wall. The ladder has a mass of m_L. Because the wall is slick, and the ice on the floor is slick, the frictional forces acting on the ladder are negligible. 

Part One:

Find a formula for the magnitude of the force that your friend must exert to keep the ladder from falling, in terms of the following variables: x,L,m_Y,m_L,theta,phi. Then use the following values to get a number for the magnitude of F→AL.

theta = 29.5 degrees

phi = 23.305 degrees

x= 2.204 meters

L = 7.6 meters

m_Y= 82 kg

m_L = 34.44kg

 

The image illustrates a simple physics problem involving a person standing on an inclined plane. 

- **Inclined Plane:** The wall and ice floor form a right angle, with the inclined plane connecting them. The inclination angle is marked as \( \theta \).
- **Person (You):** Represented by a stick figure standing on the inclined plane.
- **Distance (x):** The horizontal distance from the wall to the point directly below the person on the ice floor.
- **Force (\( \overrightarrow{F}_{AL} \)):** An arrow originating from the point where the inclined plane meets the ice floor, angled at \( \phi \) with respect to the normal (perpendicular to the ice floor).

This diagram may be used to study forces, angles, and motion on an inclined plane.
Transcribed Image Text:The image illustrates a simple physics problem involving a person standing on an inclined plane. - **Inclined Plane:** The wall and ice floor form a right angle, with the inclined plane connecting them. The inclination angle is marked as \( \theta \). - **Person (You):** Represented by a stick figure standing on the inclined plane. - **Distance (x):** The horizontal distance from the wall to the point directly below the person on the ice floor. - **Force (\( \overrightarrow{F}_{AL} \)):** An arrow originating from the point where the inclined plane meets the ice floor, angled at \( \phi \) with respect to the normal (perpendicular to the ice floor). This diagram may be used to study forces, angles, and motion on an inclined plane.
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