Two converging lenses of focal lengths 8 and 12 placed 10 cm apart. An object is placed 4 cm left of the lens with focal length 8 cm. Determine final image position
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Q: A thin, convergent lens has a focal length of 8.10 cm. If the object distance is 30.0 cm, find the…
A: Given: The focal length of the converging lens is 8.1 cm. The distance of the object is 30 cm.
Q: fa
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Q: Problem 4: An object with height 1.05 cm is placed a distance 19.5 cm in front of a thin converging…
A: The lens formula: 1di-1do=1f di = distance of the image from the lens. do = distance of the object…
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A: To solve this problem, we can use the lens and magnification formulas for thin lenses. The lens…
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Q: Problem 5: An object with height 1.1 cm is placed a distance 5.5 cm in front of a thin diverging…
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Q: A 1.00-cm-high object is placed 3.30 cm to the left of a converging lens of focal length 9.00 cm. A…
A: Given:height of object, ho = 1.00 cmobject distance from converging lens, u = −3.30 cmfocal length…
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A: Given: The lens of the concave is 30 cm. The distance of the virtual image is 10 cm.
Q: Two converging lenses are separated by 27.0 cm. The focal length of each lens is 17.0cm. An object…
A: GivenDistance of seperation between lens=27 cmFocal length of each lens=17 cmObject is placed to…
Q: Q1: An object 3cm high is located 12cm in front of a lens of 3cm focal length, and a lens of -4cm…
A: We’ll answer the first question since the exact one wasn’t specified. Please submit a new question…
Q: An object is placed a distance do = 7.0 cm in front of a negative (diverging) lens of focal length f…
A: do=7cm f=-16cm (positive =to the right of the lens )
Q: An object arrow 2 cm high is placed 20 cm from a converging lens of focal length of 10 cm. Find…
A: height of object arrow = 2 cm Object distance (d) = 20 cm focal length (f) = 10 cm A) Using lens…
Q: The Virtual Image Formed by a Diverging Lens. An object is placed 3.55 cm to the left of a diverging…
A: Given that focal length of the diverging lens or concave lens is f=-2.54 cm And object is placed…
Q: A 1.0-cm-tall object is placed 4.0 cm to the left of a converging lens with a focal length f1 = 5.0…
A: Given data as per question height of object = 1cm f1 = 5cm f2 = -8cm
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Q: 0 cm to the right of a diverging lens having a focal length of 12.0 cm. Determine the location of…
A: The diverging lens:- We know that the concave lens is the diverging lens, The refraction of light…
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A: Since the two lenses are identical, we can use the lens equation for each lens: 1f= 1do+1di where f…
Q: An object is placed at a distance of 15.0 cm from a diverging lens of focal length 30.0 cm. Which of…
A: Given: The distance of the object from the lens is do=-15 cm. The focal length of the diverging lens…
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Q: An object is placed at an object distance half the magnitude of the focal length of a converging…
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Q: On one side of a diverging lens of focal length 36.3 cm, you position an object of height 2.79 cm…
A: Focal length of diverging lens is Height of object is Height of image is Find:Object distance.
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Q: Suppose an object is held 9.5 cm from a diverging (concave) lens of focal length -22.0 cm. What is…
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Q: An object is located 15.0 cm from a converging and unknown lens combination; the converging lens has…
A: useful formula:The u-v-f relation for a lens is1v-1u=1f--(1)v-image distanceu-object distancef-focal…
Q: 7. In above figure fi = 2.0 cm, f2 = 4.0 cm and the distancce between two lens is 6.0 cm. The…
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A: The solution can be given as follows :-
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Q: A 2.0 cm tall object is placed perpendicular to the principal axis of a convex lens of focal length…
A: The lens formula and magnification formula are, Where, f = focal length u = object distance v =…
Q: Two lenses, one converging of focal length 10.0 cm and one diverging of 5.0 cm, are placed 30.0 cm…
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Q: o use a convex lens as a magnifier, the object must be closer to the converging lens than its focal…
A: Convex lens (converging lens) has to be used as a magnifier.
Q: n one side of a diverging lens of focal length 29.6 cm, you position an object of height 3.43 cm…
A: The magnification of the lens is given by The thin lens formula is given by
Q: from the lens. How far is the object's image from the lens?
A: GivenFocal length of converging lens, f=6.51 cmObject distance, u=10.1 cm
Q: Consider the optical system shown in the figure. The lens and mirror are separated by d = 1.00 m and…
A: (a) For the lens: f1 = 87.5 cm do1 = 1 m = 100 cm Using thin lens equation: 1/f1 = 1/do1 + 1/di1…
Q: An antelope is at a distance of 20.0 m from a converging lens of focal length 33.0 cm. The lens…
A: Object distance (p) = 20 mfocal length (f) = 33 cm = 0.33 m velocity of antelope away from the lens…
Q: = + 90cm; TWO LENSES ARE ARRANGED AS FOLLOWS: £₁ = + 60cm; fz THEY ARE 50 cm APART. AN OBJECT IS…
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Q: You position your eyes 10.0 cm in front of a magnifying glass with a focal length of 4.0 cm. How far…
A: Given Image distance di=-10cm focal length f=4cm object distance do
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Two converging lenses of focal lengths 8 and 12 placed 10 cm apart. An object is placed 4 cm left of the lens with focal length 8 cm. Determine final image position
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