Two control areas with the characteristics below are connected by a tie line. A load change of 150MW occurs in area 2. Assuming both areas were at nominal frequency (60HZ), calculate the new steady-state frequency (in Hz) and change in tie-line flow (in MW). 2. Area 1 Area 2 R = 0.02 pu R = 0.01 pu D = 0.9 pu D = 0.6 pu Base MVA = 100 Base MVA = 100
Two control areas with the characteristics below are connected by a tie line. A load change of 150MW occurs in area 2. Assuming both areas were at nominal frequency (60HZ), calculate the new steady-state frequency (in Hz) and change in tie-line flow (in MW). 2. Area 1 Area 2 R = 0.02 pu R = 0.01 pu D = 0.9 pu D = 0.6 pu Base MVA = 100 Base MVA = 100
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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![Two control areas with the characteristics below are connected by a tie line. A load change of 150MW
occurs in area 2. Assuming both areas were at nominal frequency (60HZ), calculate the new steady-state
frequency (in Hz) and change in tie-line flow (in MW).
2.
Area 1
Area 2
R = 0.02 pu
R = 0.01 pu
D = 0.9 pu
D = 0.6 pu
Base MVA = 100
Base MVA = 100](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb99f526a-126c-4bfb-84bd-e5f185bf8e3a%2F3566600f-9f49-4ef3-9205-0a8e8458e478%2Fsugchxo.png&w=3840&q=75)
Transcribed Image Text:Two control areas with the characteristics below are connected by a tie line. A load change of 150MW
occurs in area 2. Assuming both areas were at nominal frequency (60HZ), calculate the new steady-state
frequency (in Hz) and change in tie-line flow (in MW).
2.
Area 1
Area 2
R = 0.02 pu
R = 0.01 pu
D = 0.9 pu
D = 0.6 pu
Base MVA = 100
Base MVA = 100
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