Two charges are located in the x-y plane. If q1 = -3.05 nC and is located at (x = 0.00 m, y = 0.960 m), and the second charge has magnitude of q2 = 4.60 nC and is located at (x = 1.40 m, y = 0.600 m), calculate the x and y components, Ex and Ey, of the electric field, É, in component form at the origin, (0,0). The Coulomb force constant is 1/(4xe0) = 8.99 × 10° N · m²/C².
Two charges are located in the x-y plane. If q1 = -3.05 nC and is located at (x = 0.00 m, y = 0.960 m), and the second charge has magnitude of q2 = 4.60 nC and is located at (x = 1.40 m, y = 0.600 m), calculate the x and y components, Ex and Ey, of the electric field, É, in component form at the origin, (0,0). The Coulomb force constant is 1/(4xe0) = 8.99 × 10° N · m²/C².
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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Electric Field Components from Two Point Charges**
Two charges are located in the x-y plane. If \( q_1 = -3.05 \, \text{nC} \) and is located at \((x = 0.00 \, \text{m}, y = 0.960 \, \text{m})\), and the second charge has a magnitude of \( q_2 = 4.60 \, \text{nC} \) and is located at \((x = 1.40 \, \text{m}, y = 0.600 \, \text{m})\), calculate the x and y components, \( E_x \) and \( E_y \), of the electric field, \( \vec{E} \), in component form at the origin, (0,0). The Coulomb force constant is \( 1/(4 \pi \varepsilon_0) = 8.99 \times 10^9 \, \text{N} \cdot \text{m}^2/\text{C}^2 \).
### Calculations
For charge \( q_1 \):
- \( q_1 = -3.05 \, \text{nC} \)
- Location: (x = 0.00 m, y = 0.960 m)
For charge \( q_2 \):
- \( q_2 = 4.60 \, \text{nC} \)
- Location: (x = 1.40 m, y = 0.600 m)
### Results
The x-component of the electric field (\( E_x \)) at the origin:
\[ E_x = -16.4 \, \text{N/C} \]
The y-component of the electric field (\( E_y \)) at the origin:
\[ E_y = 36.8 \, \text{N/C} \]
*Note: The value for \( E_y \) in the given box is marked as incorrect.*
### Explanation of Graphs or Diagrams
No graphs or diagrams are provided in this specific example.
*Disclaimer: The calculations shown above are based on provided values and need to be verified for accuracy based on physical laws and principles.*
---
This transcription is suitable for educational purposes to help students understand the components of an electric field generated by multiple point charges.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F37e1db01-06d0-4e20-aae1-26f96b6814c3%2Ffcad121c-c7c5-4c59-9c12-f2f92c7607ac%2Fel19118_processed.png&w=3840&q=75)
Transcribed Image Text:**Electric Field Components from Two Point Charges**
Two charges are located in the x-y plane. If \( q_1 = -3.05 \, \text{nC} \) and is located at \((x = 0.00 \, \text{m}, y = 0.960 \, \text{m})\), and the second charge has a magnitude of \( q_2 = 4.60 \, \text{nC} \) and is located at \((x = 1.40 \, \text{m}, y = 0.600 \, \text{m})\), calculate the x and y components, \( E_x \) and \( E_y \), of the electric field, \( \vec{E} \), in component form at the origin, (0,0). The Coulomb force constant is \( 1/(4 \pi \varepsilon_0) = 8.99 \times 10^9 \, \text{N} \cdot \text{m}^2/\text{C}^2 \).
### Calculations
For charge \( q_1 \):
- \( q_1 = -3.05 \, \text{nC} \)
- Location: (x = 0.00 m, y = 0.960 m)
For charge \( q_2 \):
- \( q_2 = 4.60 \, \text{nC} \)
- Location: (x = 1.40 m, y = 0.600 m)
### Results
The x-component of the electric field (\( E_x \)) at the origin:
\[ E_x = -16.4 \, \text{N/C} \]
The y-component of the electric field (\( E_y \)) at the origin:
\[ E_y = 36.8 \, \text{N/C} \]
*Note: The value for \( E_y \) in the given box is marked as incorrect.*
### Explanation of Graphs or Diagrams
No graphs or diagrams are provided in this specific example.
*Disclaimer: The calculations shown above are based on provided values and need to be verified for accuracy based on physical laws and principles.*
---
This transcription is suitable for educational purposes to help students understand the components of an electric field generated by multiple point charges.
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