A particle of mass 25 kg, originally at rest, is subjected to a force of 50 N for 10 seconds. Find the distance traveled and the kinetic energy attained by the particle. Sketch the momentum and impulse diagrams.

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**Problem Statement:**

A particle of mass 25 kg, originally at rest, is subjected to a force of 50 N for 10 seconds. Find the distance traveled and the kinetic energy attained by the particle.

Sketch the momentum and impulse diagrams.

---

**Explanation:**

To solve this problem, we need to calculate two things: the distance traveled by the particle and the kinetic energy it attains.

1. **Calculate the Acceleration:**
   
   Using Newton's second law, \( F = ma \), where \( F \) is the force, \( m \) is the mass, and \( a \) is the acceleration.

   \[
   a = \frac{F}{m} = \frac{50 \, \text{N}}{25 \, \text{kg}} = 2 \, \text{m/s}^2
   \]

2. **Calculate the Final Velocity:**
   
   Since the particle is initially at rest, \( u = 0 \).

   Using the equation of motion \( v = u + at \):

   \[
   v = 0 + (2 \, \text{m/s}^2)(10 \, \text{s}) = 20 \, \text{m/s}
   \]

3. **Calculate the Distance Traveled:**
   
   Using the equation \( s = ut + \frac{1}{2}at^2 \):

   \[
   s = 0 \cdot 10 + \frac{1}{2}(2 \, \text{m/s}^2)(10 \, \text{s})^2 = 100 \, \text{m}
   \]

4. **Calculate the Kinetic Energy:**
   
   Kinetic Energy, \( KE = \frac{1}{2}mv^2 \):

   \[
   KE = \frac{1}{2}(25 \, \text{kg})(20 \, \text{m/s})^2 = 5000 \, \text{J}
   \]

5. **Momentum and Impulse Diagrams:**
   
   - **Momentum Diagram:** 
     The momentum is a linear graph increasing over time since the particle starts from rest, and its velocity increases uniformly.

   - **Impulse Diagram:** 
     Impulse is represented by a rectangle on a force vs. time graph, with the area under the curve
Transcribed Image Text:**Problem Statement:** A particle of mass 25 kg, originally at rest, is subjected to a force of 50 N for 10 seconds. Find the distance traveled and the kinetic energy attained by the particle. Sketch the momentum and impulse diagrams. --- **Explanation:** To solve this problem, we need to calculate two things: the distance traveled by the particle and the kinetic energy it attains. 1. **Calculate the Acceleration:** Using Newton's second law, \( F = ma \), where \( F \) is the force, \( m \) is the mass, and \( a \) is the acceleration. \[ a = \frac{F}{m} = \frac{50 \, \text{N}}{25 \, \text{kg}} = 2 \, \text{m/s}^2 \] 2. **Calculate the Final Velocity:** Since the particle is initially at rest, \( u = 0 \). Using the equation of motion \( v = u + at \): \[ v = 0 + (2 \, \text{m/s}^2)(10 \, \text{s}) = 20 \, \text{m/s} \] 3. **Calculate the Distance Traveled:** Using the equation \( s = ut + \frac{1}{2}at^2 \): \[ s = 0 \cdot 10 + \frac{1}{2}(2 \, \text{m/s}^2)(10 \, \text{s})^2 = 100 \, \text{m} \] 4. **Calculate the Kinetic Energy:** Kinetic Energy, \( KE = \frac{1}{2}mv^2 \): \[ KE = \frac{1}{2}(25 \, \text{kg})(20 \, \text{m/s})^2 = 5000 \, \text{J} \] 5. **Momentum and Impulse Diagrams:** - **Momentum Diagram:** The momentum is a linear graph increasing over time since the particle starts from rest, and its velocity increases uniformly. - **Impulse Diagram:** Impulse is represented by a rectangle on a force vs. time graph, with the area under the curve
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