Two charges 3 × 10-8 C and -2 x 10-8 C are located 15 cm apart. At what point on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.

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Q: Two charges 5 x 10^(-8) C and - 3 x 10^(-8) C are located 16 cm apart. At what point (s) on the line…

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Q: A charge of +4.70 mC is located at x = 0, y = 0 and a charge of −9.00 mC is located at x = 0, y =…

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A: q1 = 5×10-7 Cq2 = -3×10-7 C q3 = -2×10-7 C q4 = 6×10-7 C side of square (s) = 4 m

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Q: A charge of uniform density (29 nC/m) is distributed along the x axis from the origin to the point x…

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Q: Two charges, q1 = −20 nC and q2 = 28.0 nC, are separated by a distance d = 2.50 cm as shown in the…

A: The electric potential due to a point charge q at a distance r from the charge is given by,

Q: Two charges 5 × 10-8 C and –3 × 10-8 C are located 16 cm apart. At what point(s) on the line joining…

A: Basic Details The sum of the potential due to the point charges at a point is zero so the sum of…

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Q: A charge of 1.50 * 10-8 C lies on an isolated metal sphere of radius 16.0 cm.With V = 0 at infinity,…

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Q: Three point charges, Q1=15.4 μC, Q2=−38.6 μC, and Q3=57.3 μC, are arranged as shown in the figure.…

A: V=kq/r  Q1=15.4 μC, Q2=−38.6 μC, and Q3=57.3 μC  From A 50.1cm, 70.85cm, 50.1cm

Q: An object with charge q = -6.00 x 10^{-9} C is placed in a region of uniform electric field and is…

A: Given data- Charge q=-6.00×10-9 C Kinetic energy at point B is  KEB=3.00×10-7 J Electric potential…

Q: Two charges 3 × 10-7 C and –2 × 10-7 C are located 18 cm apart. At what point on the line joining…

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Q: Two charges of q₁ = 1.8 μC and 9₂ = -2.9 μC are d = 0.34 m apart at two vertices of an equilateral…

A: Given data-  Charge q1= 1.8×10-6 C , q2= -2.9×10-6 C  distance d=0.34 m

Q: Two charges 6 mC, -2 mC are separated by a distance of 1 m in air. The distance of the point between…

A: The electric potential due to a point charge is given by: V=kqr......(1)where, k is coulomb…

Q: Two charges 3 × 10-8 C and –2 × 10-8 C are located 15 cm apart. At what point on the line joining…

A: The equation for the electric potential due to a charge is given by,

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Q: A 11.5 nC charge is at x = 0 cm and a -1.5 nC charge is at x= 6.0 cm .At what point or points on the…

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A: charge = Q The electric potential = V

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Q: A dipole consisting of charges +Q and -Q.with Q = 8.0 nC. is fixed to the y-axis. +Q is located at…

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