The power rating of an incandescent light-bulb is determined under the assumption that the bulb isconnected to a standard parallel house circuit where each outlet is at the same standard voltage.• Two bulbs rated as 25W are connected in series. If one of the bulbs is replaced by a bulb rated as60W, the total current from source &(increases, decreases, stays the same).• Two bulbs rated as 25W are connected in parallel. If one of the bulbs is replaced by a bulb rated as60W, the total current from source &(increases, decreases, stays the same).Bulb 1Bulb 2(a) Bulbs in seriesBulb 1(b) Bulbs in parallelBulb 2

Answered: • Two bulbs rated as 25W are connected…

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter21: Circuits And Dc Instruments

Section: Chapter Questions

Problem 74PE: Integrated Concepts If you wish to take a picture of a bullet traveling at 500 m/s, then a very...

See similar textbooks

Related questions

Question

The power rating of an incandescent light-bulb is determined under the assumption that the bulb is
connected to a standard parallel house circuit where each outlet is at the same standard voltage.
• Two bulbs rated as 25W are connected in series. If one of the bulbs is replaced by a bulb rated as
60W, the total current from source &
(increases, decreases, stays the same).
• Two bulbs rated as 25W are connected in parallel. If one of the bulbs is replaced by a bulb rated as
60W, the total current from source &
(increases, decreases, stays the same).
Bulb 1
Bulb 2
(a) Bulbs in series
Bulb 1
(b) Bulbs in parallel
Bulb 2

Expert Solution

Step 1

To determine whether the current in series and parallel circuits.

Given:
(a) A higher rated bulb is connected in series.
(b) a higher rated bulb is connected in parallel.

To determine:
(a) whether current drawn increases, decreases or stays the same
(b) whether current drawn increases, decreases or stays the same

The power of an appliance is given by the formula:
$P = V I = \frac{V^{2}}{R} = I^{2} R$
where,
$P$ is the power,
$V$ is the voltage difference provided by the power source,
$I$ is the current drawn by the appliance and
$R$ is the resistance of the appliance

When two appliances are connected in series, the current passing through both the appliances are equal. When they are connected in parallel, the voltage across both the appliances are equal.

Trending now

This is a popular solution!

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions