### Educational Content on Series Circuit Calculation#### Circuit Diagram Explanation:The provided circuit diagram consists of a simple series circuit with the following components:1. A 9V battery.2. Two resistors in series, labeled as \( R1 \) and \( R2 \).#### Given Data:- The value of the first resistor, \( R1 \), is 10 Ω.- The value of the second resistor, \( R2 \), is 49 Ω.#### Question:Calculate the current in the circuit.- **Instruction:** - Do **NOT** include units. - Round to the hundredths place.To solve for the current in the circuit, follow these steps:1. **Calculate the equivalent resistance in the series circuit:** \[ R_{\text{total}} = R1 + R2 \] \[ R_{\text{total}} = 10\ \mathrm{\Omega} + 49\ \mathrm{\Omega} = 59\ \mathrm{\Omega} \] 2. **Apply Ohm's Law to find the current (I):** \[ V = IR \] \[ I = \frac{V}{R_{\text{total}}} \] \[ I = \frac{9\ \mathrm{V}}{59\ \mathrm{\Omega}} \] \[ I \approx 0.15 \]Therefore, the current in the circuit is approximately **0.15** when rounded to the hundredths place (without including units as instructed).

Answered: Image /qna-images/answer/23e43a89-54dd-4262-9d13-a59e565e799b.jpg

Answered: -MW- 9V = www R2 The first resistor has…

-MW- 9V = www R2 The first resistor has a value of 102 and the second resistor has a value of 49 2. What is the current in the circuit?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Temperature Variance of Resistance

Electrical resistance or simply resistance is the property of a material that opposes the free flow of electrons through it. The total amount of resistance to the flow of charges (or current) is affected by many factors like the length of the conducting material, its cross-sectional area, resistivity, and temperature.

Question

### Educational Content on Series Circuit Calculation

#### Circuit Diagram Explanation:
The provided circuit diagram consists of a simple series circuit with the following components:
1. A 9V battery.
2. Two resistors in series, labeled as \( R1 \) and \( R2 \).

#### Given Data:
- The value of the first resistor, \( R1 \), is 10 Ω.
- The value of the second resistor, \( R2 \), is 49 Ω.

#### Question:
Calculate the current in the circuit.
- **Instruction:**
- Do **NOT** include units.
- Round to the hundredths place.

To solve for the current in the circuit, follow these steps:

1. **Calculate the equivalent resistance in the series circuit:**
\[
R_{\text{total}} = R1 + R2
\]
\[
R_{\text{total}} = 10\ \mathrm{\Omega} + 49\ \mathrm{\Omega} = 59\ \mathrm{\Omega}
\]

2. **Apply Ohm's Law to find the current (I):**
\[
V = IR
\]
\[
I = \frac{V}{R_{\text{total}}}
\]
\[
I = \frac{9\ \mathrm{V}}{59\ \mathrm{\Omega}}
\]
\[
I \approx 0.15
\]

Therefore, the current in the circuit is approximately **0.15** when rounded to the hundredths place (without including units as instructed).

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