In the adjacent circuit, the voltages and values of resistance are unknown. The value of the current running through R1 is 2.9 mA going from left to right, and the current through R3 is 10.9 mA from the top of R3 to the bottom. If we remove battery 2 and replace it with a short The current through RI becomes 12mA and the current through R3 becomes 8 mA. What is the value of the current through R2 (in mA) when battery 2 is connected back while batteryl is removed and replaced with a short?: R1 R2 R3 V1 V2 O a. 9.80 O b. 4.00 O c. 8.00 O d. 12.00 O e. 17.80

Q: R4 = 2 N R = 4 2. V2 = 5 V V1 = 12 V 15 R3 = 2N R, = 3 N 12

A: I4=V2/R4=5/2=2.5 A   I4=I5+I3 I3=I4-I5=2.5-I5   I3=I2-I1   I1=I2-I3

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Q: What does this mean for the current across R2? b) How does this affect the current across R1 and R3?

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A: Given :  Resistance R1 = 44 ohmResistance R2 = 10 ohmResistance R3 = 33 ohm

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Q: The diagram below shows a circuit where R1=4 Ω, R2=6 Ω, R3=5 Ω, V1=6 Volts, V2=10 Volts, and V3=7…

A: Given, R1 = 4 ΩR2 = 6 ΩR3 = 5ΩV1 = 6 VV2 = 7 V

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A: Given, R1 = 37 ohms and R2 = 87 ohms

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