For the circuit shown below, what is the total current in the circuit? (The voltage supplied to the circuit is V= 10.0 Volts) O 1.3 A O 10 A O 20 A 0.2 A R₁ = 102 R₂= 20 Ω R₁ = 30 www R3 = 20
For the circuit shown below, what is the total current in the circuit? (The voltage supplied to the circuit is V= 10.0 Volts) O 1.3 A O 10 A O 20 A 0.2 A R₁ = 102 R₂= 20 Ω R₁ = 30 www R3 = 20
College Physics
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ISBN:9781305952300
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Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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Question
![**Question:**
For the circuit shown below, what is the total current in the circuit? (The voltage supplied to the circuit is V = 10.0 Volts)
**Circuit Description:**
- The circuit consists of four resistors:
- \( R_1 = 10 \, \Omega \)
- \( R_2 = 20 \, \Omega \)
- \( R_3 = 20 \, \Omega \)
- \( R_4 = 30 \, \Omega \)
- The resistors \( R_2 \) and \( R_3 \) are connected in parallel.
- This parallel combination is in series with \( R_1 \) and \( R_4 \).
**Answer Choices:**
- \( \, 1.3 \, \text{A} \)
- \( \, 10 \, \text{A} \)
- \( \, 20 \, \text{A} \)
- \( \, 0.2 \, \text{A} \)
**Explanation:**
To find the total current, calculate the equivalent resistance of the circuit and apply Ohm's Law:
1. Calculate the equivalent resistance of \( R_2 \) and \( R_3 \) in parallel:
\[
\frac{1}{R_{\text{parallel}}} = \frac{1}{R_2} + \frac{1}{R_3} = \frac{1}{20} + \frac{1}{20} = \frac{2}{20} = \frac{1}{10}
\]
\[
R_{\text{parallel}} = 10 \, \Omega
\]
2. Calculate the total resistance of the circuit:
\[
R_{\text{total}} = R_1 + R_{\text{parallel}} + R_4 = 10 + 10 + 30 = 50 \, \Omega
\]
3. Apply Ohm’s Law to find the current:
\[
I = \frac{V}{R_{\text{total}}} = \frac{10}{50} = 0.2 \, \text{A}
\]
**Correct Answer: \(\, 0.2 \, \text{A} \)**](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4889a1b2-cd02-493f-a3b5-7c3cbfe1f622%2F80008b3b-ae99-4dfd-a845-a9868646f2db%2Fu9mbvz8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question:**
For the circuit shown below, what is the total current in the circuit? (The voltage supplied to the circuit is V = 10.0 Volts)
**Circuit Description:**
- The circuit consists of four resistors:
- \( R_1 = 10 \, \Omega \)
- \( R_2 = 20 \, \Omega \)
- \( R_3 = 20 \, \Omega \)
- \( R_4 = 30 \, \Omega \)
- The resistors \( R_2 \) and \( R_3 \) are connected in parallel.
- This parallel combination is in series with \( R_1 \) and \( R_4 \).
**Answer Choices:**
- \( \, 1.3 \, \text{A} \)
- \( \, 10 \, \text{A} \)
- \( \, 20 \, \text{A} \)
- \( \, 0.2 \, \text{A} \)
**Explanation:**
To find the total current, calculate the equivalent resistance of the circuit and apply Ohm's Law:
1. Calculate the equivalent resistance of \( R_2 \) and \( R_3 \) in parallel:
\[
\frac{1}{R_{\text{parallel}}} = \frac{1}{R_2} + \frac{1}{R_3} = \frac{1}{20} + \frac{1}{20} = \frac{2}{20} = \frac{1}{10}
\]
\[
R_{\text{parallel}} = 10 \, \Omega
\]
2. Calculate the total resistance of the circuit:
\[
R_{\text{total}} = R_1 + R_{\text{parallel}} + R_4 = 10 + 10 + 30 = 50 \, \Omega
\]
3. Apply Ohm’s Law to find the current:
\[
I = \frac{V}{R_{\text{total}}} = \frac{10}{50} = 0.2 \, \text{A}
\]
**Correct Answer: \(\, 0.2 \, \text{A} \)**
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