Hill+ R1 -M 9V ww R2 The first resistor has a value of 46 and the second resistor has a value of 43 2. What is the voltage at the first resistor? • Do NOT include units • Round to the hundredths place

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### Parallel Resistor Circuit Analysis

#### Diagram Description:
- The diagram features a 9V voltage source connected to two resistors in series, labeled R1 and R2. 
- R1 is positioned at the top of the circuit, directly connected to the voltage source. 
- R2 is connected in series with R1, forming a closed loop with the voltage source.

#### Question:
The first resistor (R1) has a resistance value of 46Ω and the second resistor (R2) has a resistance value of 43Ω. What is the voltage across the first resistor?

- **Do NOT include units**
- **Round to the hundredths place**

To calculate the voltage across R1 in a series circuit, you will need to apply the formula and principles of Ohm's Law and series circuit analysis.

#### Solution Guide:
1. **Determine Total Resistance (R_total)**:
   - Since the resistors are in series: \( R_{\text{total}} = R_1 + R_2 \)
   - \( R_{\text{total}} = 46Ω + 43Ω = 89Ω \)

2. **Calculate the Total Current (I)**:
   - Using Ohm's Law \( V = IR \) rearranged to \( I = V/R \)
   - The total voltage (V) is 9V.
   - \( I = \frac{9V}{89Ω} = 0.1011A \) (rounded to four decimal places)

3. **Calculate the Voltage across R1 (V_R1)**:
   - Using Ohm's Law again: \( V_{R1} = I \times R_1 \)
   - Substitute the values: \( V_{R1} = 0.1011A \times 46Ω ≈ 4.65V \)
   
So, the voltage across the first resistor (R1) is approximately 4.65 volts. 

**Answer Input**: Enter the calculated voltage value for R1 (e.g., 4.65) without the unit.

This calculation helps understand how voltage divides in a series circuit based on the resistance values of the components involved.
Transcribed Image Text:### Parallel Resistor Circuit Analysis #### Diagram Description: - The diagram features a 9V voltage source connected to two resistors in series, labeled R1 and R2. - R1 is positioned at the top of the circuit, directly connected to the voltage source. - R2 is connected in series with R1, forming a closed loop with the voltage source. #### Question: The first resistor (R1) has a resistance value of 46Ω and the second resistor (R2) has a resistance value of 43Ω. What is the voltage across the first resistor? - **Do NOT include units** - **Round to the hundredths place** To calculate the voltage across R1 in a series circuit, you will need to apply the formula and principles of Ohm's Law and series circuit analysis. #### Solution Guide: 1. **Determine Total Resistance (R_total)**: - Since the resistors are in series: \( R_{\text{total}} = R_1 + R_2 \) - \( R_{\text{total}} = 46Ω + 43Ω = 89Ω \) 2. **Calculate the Total Current (I)**: - Using Ohm's Law \( V = IR \) rearranged to \( I = V/R \) - The total voltage (V) is 9V. - \( I = \frac{9V}{89Ω} = 0.1011A \) (rounded to four decimal places) 3. **Calculate the Voltage across R1 (V_R1)**: - Using Ohm's Law again: \( V_{R1} = I \times R_1 \) - Substitute the values: \( V_{R1} = 0.1011A \times 46Ω ≈ 4.65V \) So, the voltage across the first resistor (R1) is approximately 4.65 volts. **Answer Input**: Enter the calculated voltage value for R1 (e.g., 4.65) without the unit. This calculation helps understand how voltage divides in a series circuit based on the resistance values of the components involved.
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