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- Alcohols can undergo a lot of different reaction mechanims. If the alcohol group (OH) is attaached to an aromatic core, how will the chemistry change as compared to a typical alkyl alcohol? A) The OH group will become more polarised and more nucleophilic. B) The OH group will become more susceptible to oxidation C) The OH group will become more polarised and therefore basic D) The OH group will become more polarised and therefore acidic.Assign the proton and carbon NMR spectroscopy for the product of your reaction. Show the proton and carbon NMR peaks. This can be the NMR graph OR a list of peaks labeled 1,2,3 or a,b,c. Label the 1H-NMR spectral data (1,2,3 or a,b,c) and match the peaks to ALL the product molecule's H by labeling them (1,2,3 or a,b,c). Show that you know which 1H-NMR peaks correspond to each hydrogen atoms on your molecule. Label the 13C-NMR spectral data (1,2,3 or a,b,c) and match the peaks to ALL the product molecule's C by labeling them (1,2,3 or a,b,c). Show that you know which 13C-NMR peaks correspond to each hydrogen atoms on your molecule. CO,H NH2*HCIIn each reaction box, place the best reagent and conditions from the list provided. 1) Br 2) 3) 4) DEET (the active ingredient in over the counter insect repellant) 5) Answer Bank Mg, Et,0 HN(CH, CH, ), (1 equiv.) H,O* CH,COOH CH,CH,NH, CH,CH, Br NH(CH,CH,),(2 cquiv.) НСООСH, H,CO НСООН CH, CH, OH NaCN NaNH, Br,, FeBr, SOCI, CO,
- 10. E to CH3ONa a) Br₂ Br2 1. Mg /ether khan (A) (B) (C) (D) hv FeBr3 hv 2. CO2 3. H3O+ C1 B2 B3 B1 KMnO4 H+ C1 Mg, ether CHO b) 1. CH3Mgl H2SO4 HBr 1. Mgether khan A B D to 2. H3O+ peroxide 2. H₂C-CH2 ° CH3COCI AICI 3 1. C1 1. 03 G F E 2. H3O+ 2. Na₂S 3. H3O+6. Provide the products for the reactions. Take note of the changes and how they tie together for the overall result. Br H20 NANH2 З еq Br Br NaNH2 2 eq Br 1. NANH2, 3 eq 2. Hао Br2 1. NaNH2, 3 eq 2. H2O OH conc. H2SO4 Br2 heatSeloct the methodis) that would produce the compound shown on the right as the major product NABH4 РСС 1. OCH3 CH;OH CH-Cl 1) LIAIH4. ether, 2) H20 2. PCC OCH3 CH,CI2 1) DIBALH, ether H+ 3. LOCH3 2) H20 H20 O 1 and 2 O 2 only O 3 only O 2 and 3
- Alcohols are acidic in nature. Therefore, a strong base can abstract the acidic hydrogen atom of the alcohol in a process known as deprotonation. The alcohol forms an alkoxide ion by losing the proton attached to the oxygen atom of the hydroxyl ( -OH) group. The alkoxide formed can act as a base or a nucleophile depending on the substrate and reaction conditions. However, not all bases can abstract the acidic proton of alcohols and not all alcohols easily lose the proton. Deprotonation depends on the strength of the base and the acidity of the alcohol. Strong bases, such as NaNH2, can easily abstract a proton from almost all alcohols. Likewise, more acidic alcohols lose a proton more easily. Determine which of the following reactions would undergo deprotonation based on the strength of the base and the acidity of the alcohol. Check all that apply. ► View Available Hint(s) CH3CH,OH + NH3 →CH,CH,O-NH CH3 CH3 H3C-C-H+NH3 → H3 C-C-H OH O-NH CH3CH2OH + NaNH, → CH3CH,O-Na* + NH3 CHC12 Cl₂…In both examples below the reactants shown are combined to bring about a nucleophilic substitution (SN1, SN2) and/or elimination (E1, E2) reaction. What is the major reaction that takes place in each case? BrCH₂COCH3 CH3 CH3CH₂CCH3 NaCN CH3OH H₂O SN2 M7. Reaction Scheme. NH₂ NH2 or two differnet methods (no same steps/reagents) C5H12N2 1. xs Mel, xs K2CO3 2. Ag2O, H₂O 3. heat Br2, xs NaOH, xs H₂O OHC 1.03 2. DMS CHO
- Drawthe MAJOR product(s) of the followingreaction. 1) ВН,-THF 2) H,0г. NaOH 3) РСС, СН,Clz 1. он 1) NaH 2) 8 3) Н,о 2. но. O,N AICI, Br 1) NaCN, DMSO 2) excess LAH 3) H20 4. 3.Q6. Predict the structures of the final products of the following transformations. 1. NaNH, NH, CI 2, L, NH Q7. Identify the products of the following sequence of reactions. for Br KOH, CH₂CH₂OH BH₂/H₂O/H₂O₂, OHNAOH H2NNH2 5) 4) 3) Excess CH3OH H3O* РСС Br START HERE 1) Mg 2) CH3CHO 1) 2) 6)? Br KMNO4 DIBAL, 7) 8) H3C SOC22 Ag20 NH4OH Ph3P:CHCH2CH3 9) 14) 15) Benzene AlCl3 03 DMS C2H5OH, H3O* 10) 16) 17) HCN 11) H3O* 12) NH3 13)