6. Provide the products for the reactions. Take note of the changes and how they tie together for the overall result. Br H20 NANH2 3 eq Br Br NaNH2 2 eq Br 1. NANH2, 3 eq 2. Нао Br2 1. NaNH2, 3 eq 2. Н2о OH conc. H2SO4 Br2 heat
6. Provide the products for the reactions. Take note of the changes and how they tie together for the overall result. Br H20 NANH2 3 eq Br Br NaNH2 2 eq Br 1. NANH2, 3 eq 2. Нао Br2 1. NaNH2, 3 eq 2. Н2о OH conc. H2SO4 Br2 heat
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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- Alkyl dibromide (R-Br)
**Reagent:**
- Sodium amide (NaNH₂), 3 equivalents
**Addition:**
- Water (H₂O)
2. **Reaction 2**
**Reactants:**
- Alkyl dibromide (R-Br)
**Reagent:**
- Sodium amide (NaNH₂), 2 equivalents
3. **Reaction 3**
**Reactants:**
- Alkene (R-CH=CH₂)
**Reagent:**
- Bromine (Br₂)
**Addition Sequence:**
1. Sodium amide (NaNH₂), 3 equivalents
2. Water (H₂O)
4. **Reaction 4**
**Reactants:**
- Alcohol (R-OH)
**Reagent:**
- Concentrated sulphuric acid (conc. H₂SO₄)
**Reaction Condition:**
- Heat
**Additional Reagent:**
- Bromine (Br₂)
**Addition Sequence:**
1. Sodium amide (NaNH₂), 3 equivalents
2. Water (H₂O)
#### Explanation of the Reactions:
- **Reaction 1 and 2:**
These reactions involve alkyl dibromides undergoing elimination reactions facilitated by a strong base (NaNH₂), yielding alkynes after treatment with water.
- **Reaction 3:**
This reaction includes the addition of bromine to an alkene to form 1,2-dibromoalkane, followed by dehydrohalogenation with sodium amide which forms an alkyne.
- **Reaction](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3116f7b7-ffc9-4d01-9cec-77f4e06225cd%2Fce542dc9-6fee-47bc-a216-a2558ab93a94%2F7drpnbr_processed.png&w=3840&q=75)
Transcribed Image Text:### Reactions and Their Products
#### Problem 6:
Provide the products for the reactions. Take note of the changes and how they tie together for the overall result.
1. **Reaction 1**
**Reactants:**
- Alkyl dibromide (R-Br)
**Reagent:**
- Sodium amide (NaNH₂), 3 equivalents
**Addition:**
- Water (H₂O)
2. **Reaction 2**
**Reactants:**
- Alkyl dibromide (R-Br)
**Reagent:**
- Sodium amide (NaNH₂), 2 equivalents
3. **Reaction 3**
**Reactants:**
- Alkene (R-CH=CH₂)
**Reagent:**
- Bromine (Br₂)
**Addition Sequence:**
1. Sodium amide (NaNH₂), 3 equivalents
2. Water (H₂O)
4. **Reaction 4**
**Reactants:**
- Alcohol (R-OH)
**Reagent:**
- Concentrated sulphuric acid (conc. H₂SO₄)
**Reaction Condition:**
- Heat
**Additional Reagent:**
- Bromine (Br₂)
**Addition Sequence:**
1. Sodium amide (NaNH₂), 3 equivalents
2. Water (H₂O)
#### Explanation of the Reactions:
- **Reaction 1 and 2:**
These reactions involve alkyl dibromides undergoing elimination reactions facilitated by a strong base (NaNH₂), yielding alkynes after treatment with water.
- **Reaction 3:**
This reaction includes the addition of bromine to an alkene to form 1,2-dibromoalkane, followed by dehydrohalogenation with sodium amide which forms an alkyne.
- **Reaction
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