Two 6-in.-wide wooden boards are to be joined by splice plates that will be fully glued onto the contact surfaces, as shown in the figure. The glue to be used can safely provide a shear strength of 100 psi. Determine the smallest allowable length L that can be used for the splice plates for an applied load of P = 20,000 Ib. Note that a gap of a = 0.4 in. is required between boards (1) and (2). (1) Answer: L = i in.
Two 6-in.-wide wooden boards are to be joined by splice plates that will be fully glued onto the contact surfaces, as shown in the figure. The glue to be used can safely provide a shear strength of 100 psi. Determine the smallest allowable length L that can be used for the splice plates for an applied load of P = 20,000 Ib. Note that a gap of a = 0.4 in. is required between boards (1) and (2). (1) Answer: L = i in.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![Two 6-in.-wide wooden boards are to be joined by splice plates that will be fully glued onto the contact surfaces, as shown in the figure.
The glue to be used can safely provide a shear strength of 100 psi. Determine the smallest allowable length L that can be used for the
splice plates for an applied load of P = 20,000 Ib. Note that a gap of a = 0.4 in. is required between boards (1) and (2).
P
(1)
(2)
Answer: L = i
in.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F41a83a91-988f-4ed8-8fc8-bb81186309ed%2F5a63e383-a884-4093-a4d8-abf1949e22c7%2Fz7i3wjn_processed.png&w=3840&q=75)
Transcribed Image Text:Two 6-in.-wide wooden boards are to be joined by splice plates that will be fully glued onto the contact surfaces, as shown in the figure.
The glue to be used can safely provide a shear strength of 100 psi. Determine the smallest allowable length L that can be used for the
splice plates for an applied load of P = 20,000 Ib. Note that a gap of a = 0.4 in. is required between boards (1) and (2).
P
(1)
(2)
Answer: L = i
in.
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