INSTRUCTIONS:●Please write clearly and understandable way.Write all the corresponding Given with their corresponding symbols and units.Draw/Illustrate the diagram/circuit or drawings that is related to the problem,IF POSSIBLE, which is HIGHLY REQUIRED.Solve in step-by-step, no shortcut.Underline twice the Final Answer.PROBLEM:Two 220-V, 1-phase electrical furnaces take loads of 350 kW and 500 kW respectively ata power factor of 0.6 lagging. The main supply is at 11-kV, 3-phase, 50 Hz. Calculatecurrent in the 3-phase lines which energize a Scott-connected transformer combination.the full-load with normal heating

The transformer combination is shown below. K=2201100=150

Two 220-V, 1-phase electrical furnaces take loads of 350 kW and 500 kW respectively at a power factor of 0.6 lagging. The main supply is at 11-kV, 3-phase, 50 Hz. Calculate current in the 3-phase lines which energize a Scott-connected transformer combination.

Two 220-V, 1-phase electrical furnaces take loads of 350 kW and 500 kW respectively at a power factor of 0.6 lagging. The main supply is at 11-kV, 3-phase, 50 Hz. Calculate current in the 3-phase lines which energize a Scott-connected transformer combination.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

Can efficiency be determined for a single phase transformer under open circuit test ?and if so what's its formula .keep in mind open circuit test .
a)Discuss 5 differences between standard microprocessors and microcontrollers b)Describe the RISC design philosophy c)List and describe 10 features of the Atmel ATmega2560 AVR microcontroller
5. A 50-kVA 20,000/480-V 60-Hz single-phase distribution transformer is tested with the following results: Open-circuit test (measured from secondary side) Voc 480 V Ioc = 4.1 A Poc 620 W Short-circuit test (measured from primary side) Vsc=1130 V Isc = 1.30 A Psc=550 W a) Find the per-unit equivalent circuit for this transformer at 60 Hz. b) What is the efficiency of the transformer at rated conditions and unity power factor? What is the voltage regulation at those conditions? c) What would the ratings of this transformer be if it were operated on a 50-Hz power system? d) Sketch the equivalent circuit of this transformer referred to the primary side if it is operating at 50 Hz. e) What is the efficiency of the transformer at rated conditions on a 50 Hz power system, with unity power factor? What is the voltage regulation at those conditions? f) How does the efficiency of a transformer at rated conditions and 60 Hz compare to the same physical device running a 50 Hz?
Find the elements of the equivalent circuit relative to the secondary of a single-phase transformer. The no- load voltages in the primary and secondary circuit are 200 and 400 volts, respectively, and at a frequency of 50 Hz. The primary no-load current at a voltage of 200 volts is 0.7 amps and the losses in the core are 70 watts. The resistance and reactance of the primary are 3.2 and 1.25 ohms, respectively. Secondary resistance and reactance 6. 0, 0.07 ohms, respectively. Draw the equivalent circle, showing the values of its elements.
A 11000/230 V, 150-kVA, 1-phase, 50-Hz transformer has core loss of 1.4 kWand full load copper loss of 1.6 kW. Determine (a) the kVA load for max. efficiency and(b) the value of max. efficiency at unity power factor
Find the elements of the equivalent circuit relative to the secondary of a single-phase transformer. The no-load voltages in the primary and secondary circuits are 200,400 volts, respectively, at a frequency of 50 Hz The primary no-load current at voltage 200 equals 0.7 amps and pulp losses equal to 70 watts Primary resistance and reactance 3.2 , 1.25 In order, the reactance of the resistance and the coil 0.6 , 0.7 Then draw the equivalent circle, explaining the values
Find the elements of the equivalent circuit attributed to the secondary of a single-phase transformer. The no-load voltages in the primary and secondary circuit are 200 volts and 400 volts, respectively, with a frequency of 50 Hz. The primary no-load current at the voltage of 200 volts is 0.7 amperes and the loss of the core is equal to 70 watts. The resistance and reactance of the primary are 3.2 ohms and 1.25 ohms, respectively. The resistance and reactance of the secondary are 0.6 ohm and 0.07 ohm, respectively. Draw the equivalent circle, showing the values of its elements.
A 36/240 V phase transformer, belonging to a phase measured from the no-load (idle) run and short-circuit test. values are given in the table below. High voltage by applying rated voltage to the low voltage winding (The winding ends were left unloaded and the results of the no-load test results were obtained. By applying nominal current to the high voltage windings, the low voltage windings were short-circuited, and the results of the short circuit test were obtained. In direct current test 1 V direct voltage is applied to the low voltage winding, and the transformer draws 500 A direct current. All equivalent Calculate the circuit elements as moved to the low voltage side. Idle run test: Voltage : 36V Power : 68W Current : 2,8A Short circuit test: Voltage : 15V Power : 325W Current : 42,2A
A 3.5 kV / 120V, 50 Hz, single phase transformer is to have an approximate e.m.f per turn of 33V and operate with a maximum flux density of 1.35T. Determine, (a) The number of primary and secondary turns. (b) The cross sectional area of the core.
2- Proved that a resistance of (R¡ )in primary is equivalent to (R1 K’ )in secondary.? 3- A 40-kVA, 3,300/240-V, 50 Hz, 1-phase transformer has 660 turns on the primary. Determine (a) the number of turns on the secondary (b) the maximum value of flux in the core (c) the approximate value of primary and secondary full-load currents. Internal drops in the windings are to be ignored.
A 3-phase, 50 Hz, oil cooled core type transformer has the following dimensions: distance between core centres 0.4 m, height of window 0.48 m, dia of circumscribing circle 0.28 m. The flux density in the core is 3.00 Wb/m² and the current density in the conductors is 5.0 N/mm². Estimate the KVA rating. Assume a window space factor of 0.4 and a core area factor= 0.56 the core is 2 stepped.