Try this with an electron: An electron is placed near the negative plate of the capacitor in the image 8.2 above. The electron moves (starting from rest) to position x=1.10E-3 m inside the capacitor but does not reach the positive plate. What is the electron's speed (in m/s) at this position? Please report answers to 3
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- Consider a parallel plate capacitor whose plates have a charge density n. An anti-proton (a particle with the same mass as a proton, but opposite charge) starting at the positive plate is shot at a velocity of vo= 30, 000 m/s towards the negative plate. 1. What is the minimum electric field strength needed between the plates if the proton is not to hit the top plate? 2. Describe the anti-proton's trajectory. 12° Vo 45° 2.0 cm ++++Help me pleaseGiven the following Configurations of Equipotential lines, sketch the electric fields in these regions. (See attached figures) a. A negatively charged flat sheet (in 3-dimensions, it is a bar) and a positively charged point charge, as shown in the figure on the left. b. two positive point charges. Here consider the negative charge to be spread out evenly at infinity (very far from the charge, as shown in the figure on the right_
- (IGNORE PART A) d. Calculate the electric potential at Point A AND at Point B. e. What is the change in electric potential energy if a charge of –3 nC is moved from Point A to Point B?Given a rectangular configuration of charges with side a=0.40 cm and the other side b=0.50 cm, where |q1|=|92| = |g3| = 60nC. Please note that q2 is negatively charged 1. What is the voltage at the upper left-hand corner of the square? 2. How much work does it take to bring an electron to the fourth corner? 3. How much energy did it take to assemble these charges? (Involved problem!) 9₁ D b aSuppose you have a capacitor composed of two disks of diameter D separated by a distance a with Da. What happens to the strength of the electric field between the plates if a is decreased by a factor of two (i.e. the separation between the plates decreases to half its initial value)? What would happen to the strength of the electric field outside the plates?
- I got this question wrong and keep getting different values with the calculations I am doing. If possible, please include the steps so I may understand where I went wrong with my calculations. (a). What is the capacitance? (in F) (b). What is the potential difference between the plates? (in v) (c). What is the magnitude of the electric field between the plates? (in V/m)Consider the diagram below of two square-plate capacitors. For the capacitor on the right, if the voltage is held constant by a voltage source and the plates are separated by a factor xºd, what is the new charge on the plates, Q: after the separation? + Letx-3 Express your answer in terms of Q. For example: 5Q or 5 Q. Do not use or any multiplication symbols. If your answer has a decimal, round to one decimal place. |Q' = ? Q' = ? xdquestion 1 and 2 please
- Ml0.0Energy Stored in Electric Fields: The energy stored in a capacitor is UE = CAVC² We can understand this since it takes energy to push charges of the same sign together on each plate. However, we can also think of this energy as being stored in the electric field created between the plates. 3. Consider a air-filled parallel plate capacitor with plates of area A and gap width H. There is a voltage difference AVC between the plates. For a parallel plate capacitor the capacitance is UE ==CAV² = C = € A H UE = UE/Volume = H and AVC = EH. a. Substitute these the expressions for C and AVC into the expression for the energy stored in the capacitor to write the energy in terms of the electric field E. de vioolav A Ē b. Divide your expression by the volume AH of the capacitor to write the electric energy density in terms fo the electric field E. year AVCplease answer G and H. previous questions are above to help:)