Parallel plate capacitor (3 points) Consider an ideal parallel plate capacitor as in the figure below. Assume that the electric field between the two plates is uniform, and that you can neglect any edge/boundary effects. Consider the electric potential at points A,B,C and D marked on the figure in the space between the two plates. Call them VA, VB, Vc and Vp, respectively. Use the signs >, < and = to express the relationships between these four potentials. A B
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- Predict: what is the ratio of the final energy to the initial energy, Uf/Ui, if the final state has been achieved by the following sequence of steps (starting from the initial situation)? Initial Area is 100 mm^2 and initial separation distance is 10 mm. the battery is disconnected the area is quadrupled the dielectric is taken out of the capacitor the separation is halved. Recreate the the table previously given below. Add a column to solve for the ratio.Please, I need help with this problem. PLEASE, provide a DETAILED explanation with words and formulas step by step please. I will like your answer if you provide this. Thank you in advance!I only want 4 and 5. I pasted the whole question as a reference only. Two parallel plates, each having area A = 3085cm2 are connected to the terminals of a battery of voltage Vb = 6 V as shown. The plates are separated by a distance d = 0.49cm. You may assume (contrary to the drawing) that the separation between the plates is small compared to a linear dimension of the plate. 1) What is C, the capacitance of this parallel plate capacitor? 2) What is Q, the charge stored on the top plate of the this capacitor?. 3) A dielectric having dielectric constant κ = 3.4 is now inserted in between the plates of the capacitor as shown. The dielectric has area A = 3085 cm2and thickness equal to half of the separation (= 0.245 cm) . What is the charge on the top plate of this capacitor? 4) What is U, the energy stored in this capacitor? 5) The battery is now disconnected from the capacitor and then the dielectric is withdrawn. What is V, the voltage across the capacitor?
- Subject: Electrmagnetics A capacitor consists of three concentric spherical shells with radii R, 2R, and 3R. The inner and outer shells are connected by a wire so they are at the same potential. The shells start neutral, and then a battery transfers charge from the middle shell to the inner and outer shells.a. If the final charge on the middle shell is -Q, what are the charges on the inner and outer shells? Your answer should be a function of Q.b. Determine the electrostatic energy of this system in terms of Q.Question BIn examining Fig. 5, how would you describe the direction and strength of electric field vector, nature of the electric field sources, and electrostatic potential surfaces given the equipotential lines, and even the potential differences at: a. a single positive charge (Fig. 5a): b. an electric dipole (Fig. 5b): c. at two equal positive charges (Fig. 5b):
- I'm needing help on parts a, e, and f, please2 sphereical conductors with radii r2>r1 were initially charged and then connected by a wire with negligible resistance. Select the statement(s) about charges (q1 and q2), electric potentials (v1=kq1/r1 and v2=kq2/r2) and surface charge densities on conductors 1 and 2 after connection that is(are) correct: There may be more than 1 correct answer a) potentialv1=v2 b)potential v1>v2 because the radius is smaller c) surface charge density o1<o2 d)charge q1<q2 e)magnitude of electric field on the surface of the conductor E1>E2A spherical capacitor consists of an inner spherical shell of radius R1 and an outer spherical shell of radius R2, as shown above. Our goal is to calculate the capacitance of this configuration of electrodes.To start, suppose the inner sphere has a charge +Q and the outer sphere an equal but opposite charge -Q. Find the capacitance using the following steps:1. Use Gauss's law to find an expression for the electric field in the region between the two spheres.2. Find an expression for the potential difference between the spheres from the electric field (you'll have to integrate the electric field from the negative electrode to the positive one).3. Calculate the capacitance from C = Q / ΔV.Suppose in this case that R1 = 2.00 cm and R2 = 4.30 cm. What is the value of the capacitance?