A random sample of 250 local designers were interviewed and asked about their preferred color. Results showed that 27 preferred the color green. Construct a 95% confidence interval for the true proportion of local designers who preferred the color green.
Q: Isabel Myers was a pioneer in the study of personality types. According to one of her surveys, in a…
A: Solution
Q: In a Gallup poll of 804 randomly selected adults living in the 50 U.S. states and the District of…
A: Answer x =466n =804Confidence interval =95%
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Q: There are 3000 beads of various colors in a jar. In a sample of 125 beads, 40% were red. Calculate…
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Q: Of 125 adults selected randomly from one town, 28 of them smoke. Construct a 99% confidence interval…
A: It is given that out of 125 adults in one town, 28 of them smoke. That is the value of n is 125 and…
Q: When Mendel conducted his famous genetics experiment with peas, one sample of offspring consisted of…
A: Obtain the 95% confidence interval estimate of the percentage of yellow peas. The 95% confidence…
Q: In a random sample of 100 customers, the items that customers purchased were tracked. It was found…
A: Given,sample size(n)=100sample proportion(p^)=0.171-p^=1-0.17=0.83α=1-0.90=0.1α2=0.05Z0.05=1.645
Q: A survey of 120 female freshmen showed that 9 did not wish to work after marriage. Find the 99%…
A:
Q: Of 260 employees selected randomly from one company, 18.46 % of them commute by carpooling.…
A: Given data, n=260 p= 18.46% = 0.1846 The z value at 90% confidence is 1.64
Q: Use the sample data and confidence level given below to complete parts (a) through (d). In a study…
A: a.
Q: A bank randomly selected 200 checking-account customers and found that 110 of them also had savings…
A: Given that A bank randomly selected 200 checking-account customers and found that 110 of them also…
Q: A poll of 827 students at Alpha state college found that 61% of those polled preferred a quarter…
A: It is given that the proportion of the students who preferred a quarter system to a trimester…
Q: When 302 college students are randomly selected and surveyed, it is found that 122 own a car. What…
A: E have to find point estimate with with confidance interval..
Q: We want to estimate the proportion of vegetarian restaurants in a country. We observe 20 such…
A: We observe 20 such restaurants out of 100 p⏞ =xn=20100=0.5 90% confidence interval for the…
Q: n a survey of 2480 golfers, 372 said they were left-handed. Construct a 92% confidence interval for…
A: The given data is appropriate for single proportion confidence interval . because it is a large…
Q: 324 out of a simple random sample of 400 students hated their online math course. Find a 99%…
A: Given: Number of students that hated the online math course (y) = 324 Number of students (n) = 400…
Q: when 282 college students are randomly selected and surveyed, it is found that 109 own a car. find a…
A: It is given that sample size (n) is 282 and x is 109.
Q: A recent study showed that among 725 randomly selected subjects who completed 4 years of college,…
A: We have given that, Favorable cases (X) = 139 and Sample size (n) = 725 Then, We will find 95%…
Q: 2. What is the chance of having four children and all of them being boys?
A: we have to find probability of family have four children and all of them are boys =?
Q: n a randomly selected group of 750 automobile deaths, 240 were alcohol related. Construct a 95%…
A: Given that, x = 240, n = 750 The value of sample proportion is,
Q: andom sample of 1200 high school freshmen was taken and it was found that 559 of them were reading…
A: The population proportion (p) will be proportion of high school freshman who reads at or above their…
Q: A survey of 800 women shoppers found that 15% of them shop on impulse. What is the 95% confidence…
A: n = 800p^ = 0.1595% CI for p = ?
Q: A survey found that 39 of 66 people who don't drink coffee often have trouble sleeping and 44 of 88…
A: Solution: Let X1 be the number of noncoffee drinkers who have trouble sleeping, n1 be the sample…
Q: A doctor would like to estimate the mean difference in the number of hours of sleep for seniors in…
A: Random sample of 50 high school seniors Random sample of 50 seniors from the colleges in his county…
Q: In a sports poll, 142 of 500 randomly selected Americans indicated that they consider themselves to…
A: Given that, In a sports poll, 142 of 500 randomly selected Americans indicated that they consider…
Q: Of 254 randomly selected medical students, 25 said that they planned to work in a rural community.…
A: It is given that, the number of students said that they planned to work in natural community (x)…
Q: When 328 college students are randomly selected and surveyed, it is found that 122 own a car. Find…
A: We want to find 95% CI for population proportion (p)
Q: An ice cream shop wants to know how many customers enjoy their newest flavor. 200 randomly selected…
A:
Q: Suppose a marketing company computed a 96% confidence interval for the true proportion of customers…
A: The objective of the question is to understand the meaning of the given 96% confidence interval for…
Q: As health insurance costs and the number of disabled employees increase, more companies are firing…
A: Confidence Interval: The form of the confidence interval is, CI = Point estimate ± Margin of error…
Q: An internet service provider sampled 540 customers and found that 55 of them experienced an…
A:
Q: A marketing survey involves product recognition in New York and California. Of 558 New Yorkers…
A:
Q: A marketing study by Ford Motor Company finds that 320 of the 650 buyers of compact cars were women.…
A: Let the population proportion of women who bought compact cars be P Given: Sample size n =…
Q: A genealogist randomly selected 203 Americans and asked about their heritage. Of those randomly…
A:
Q: Construct a 95% confidence interval for the proportion of college students who say they own their…
A: Given : n=410 , X=155 , α=0.05 We want to find the 95% confidence interval for the proportion of…
Q: An actuary is interested in estimating the proportion of young adults who plan to have children…
A: We need to construct the 99% confidence interval for the population proportion. We have been…
Q: In a random sample of 250 high school students, it was found that 85.2% (213) of them later…
A:
Q: f 260 employees selected randomly from one company, 18.46% of them commute by carpooling. Construct…
A: Given data, n=260 p=18.46% =0.1846 z-value at 98% confidence is Zc=2.326
Q: Out of 54 randomly selected patients of a local hospital who were surveyed, 49 reported that they…
A: Giventotal patients randomly selected =n = 54total patients who were satisfied = 49proportion of…
Q: thirteen out of the 147 randomly selected faculty members who were surveyed at a communty college…
A: Solution: Let X be the number of faculty members at the community college who know sign language and…
Q: A Gallup poll of 1487 adults showed that 43% of the respondents have Facebook pages. Construct a…
A: Confidence Interval: In statistics, we can say a range of values of the specified population…
Q: In one state, of 927 fatalities, 632 were alcohol-impairing-driving related. Construct the 95%…
A:
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- A recent survey showed that 42% of US employers were likely to require higher employee contributions for health care coverage. Suppose the survey was based on a sample of 500 companies. Find the 99% confidence interval for the proportion of all companies likely to require higher employee contributions for health care coverage. (Round to four decimal places)Michelle, a student studying music, randomly sampled fellow music majors and asked whether they listen to music while they study. The resulting confidence interval for the proportion of music students who listen to music while studying is (0.09, 0.26). What is the margin of error?In a survey of 1000 households, 800 had cell phones but no landline. Construct a 95% confidence interval for the proportion of all households with a cell phone but no landline.
- A report states that 46% of home owners had a vegetable garden, how large A sample is needed to estimate the true proportion of home owners who have vegetable gardens to within 3% with 95% confidence.in a survey of 692 lesbian, gay, bisexual, or transgender U.S adults 378 said that they consider themselves bisexual. Construct a 90% confidence interval for the population proportion of lesbian, gay, bisexual, or transgender U.S adults who consider themselves bisexual.6) When 415 college students were surveyed, 175 said they own their car. Construct a 95% confidence interval for the proportion of college students who say they own their cars.
- Car and Driver Magazine tested a random sample of 9 hybrid cars and found their MPG to be 42, 51, 39, 44, 52, 48, 51, 44, and 47. Construct a 95% confidence interval for the population variance.A newspaper article reported that 400 people in one state were surveyed and 70% were opposed to a recent court decision. The same article reported that a similar survey of 500 people in another state indicated opposition by only 40%. Construct a 95% confidence interval of the difference in population proportions based on the data.When 370 junior college students were surveyed, 145 said they have a passport. Construct a 95% confidence interval for the proportion of junior college students that have a passport. Round to 2 decimal places.
- When 258 college students are randomly selected and surveyed, it is found that 106 own a car. Find a 99% confidence interval for the true proportion of all college students who own a car.In a survey, 545 college students are randomly selected and asked whether or not they own a car. Of those surveyed, it is found that 210 own a car. Use this data to find a 99% confidence interval for the true proportion of all college students who own a car.Wildlife biologists inspect 180 deer taken by hunters and find 36 of them carrying Lyme disease ticks. Calculate a 95% confidence interval for the proportion of deer that carry Lyme disease ticks.