6) When 415 college students were surveyed, 175 said they own their car. Construct a 95% confidence interval for the proportion of college students who say they own their cars.

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**Problem Statement:**

When 415 college students were surveyed, 175 said they own their car. Construct a 95% confidence interval for the proportion of college students who say they own their cars.

**Solution:**

To solve this problem, follow these steps:

1. **Identify the Sample Proportion (p̂):**

\[ 
p̂ = \frac{x}{n} = \frac{175}{415}
\]

2. **Calculate the Standard Error (SE):**

\[ 
SE = \sqrt{\frac{p̂(1 - p̂)}{n}}
\]

3. **Determine the Z-score for 95% Confidence Interval:**

- For a 95% confidence level, the Z-score is approximately 1.96.

4. **Construct the Confidence Interval:**

\[ 
\text{Confidence Interval} = p̂ \pm Z \times SE
\]

This will give you the range within which the true proportion of college students who own their cars is likely to fall with 95% confidence.
Transcribed Image Text:**Problem Statement:** When 415 college students were surveyed, 175 said they own their car. Construct a 95% confidence interval for the proportion of college students who say they own their cars. **Solution:** To solve this problem, follow these steps: 1. **Identify the Sample Proportion (p̂):** \[ p̂ = \frac{x}{n} = \frac{175}{415} \] 2. **Calculate the Standard Error (SE):** \[ SE = \sqrt{\frac{p̂(1 - p̂)}{n}} \] 3. **Determine the Z-score for 95% Confidence Interval:** - For a 95% confidence level, the Z-score is approximately 1.96. 4. **Construct the Confidence Interval:** \[ \text{Confidence Interval} = p̂ \pm Z \times SE \] This will give you the range within which the true proportion of college students who own their cars is likely to fall with 95% confidence.
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