TReferences]Use the References to access important values if needed for this question.The free energy change for the following reaction at 25 °C, when [Cr= 6.98x10 M and (Ni) = 1.15 M, is 296 kJ:%3!2Cr"(6.98x10 M) + 3Ni(s)-2Cr(s) + 3NI*(1.15 M) AG = 296 kJWhat is the cell potential for the reaction as written under these conditions?Answer:Would this reaction be spontaneous in the forward or the reverse directionforwardreverse

Answered: Image /qna-images/answer/c9ec11d6-eae2-4ed6-a39c-fdbb583aa411.jpg

TReferences] Use the References to access important values if needed for this question. The free energy change for the following reaction at 25 °C, when [Cr= 6.98x10 M and (Ni)- 1.15 M, is 296 kJ: %3! 2Cr"(6.98x10 M) + 3Ni(s)2Cr(s) + 3N"(1.15 M) AG - 296 kJ What is the cell potential for the reaction as written under these conditions? Answer: V Would this reaction be spontaneous in the forward or the reverse direction forward reverse

TReferences] Use the References to access important values if needed for this question. The free energy change for the following reaction at 25 °C, when [Cr= 6.98x10 M and (Ni)- 1.15 M, is 296 kJ: %3! 2Cr"(6.98x10 M) + 3Ni(s)2Cr(s) + 3N"(1.15 M) AG - 296 kJ What is the cell potential for the reaction as written under these conditions? Answer: V Would this reaction be spontaneous in the forward or the reverse direction forward reverse

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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