The free energy change for the following reaction at 25 °C, when [H] = 8.48x103 M and [Fe³+] = 1.12 M, is 161 kj: 2.00H*(8.48×103 M) + 2Fe2(aq) +H₂(g) + 2Fe³*(1.12 M) AG=161 kj What is the cell potential for the reaction as written under these conditions? Answer: Would this reaction be spontaneous in the forward or the reverse direction? (

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The free energy change for the following reaction at 25 °C, when [H] = 8.48x103 M and [Fe³+] = 1.12 M, is 161 kj:
2.00H*(8.48×10-3 M) + 2Fe2+ (aq)H₂(g) + 2Fe³+ (1.12 M) AG=161 kj
What is the cell potential for the reaction as written under these conditions?
Answer:
Would this reaction be spontaneous in the forward or the reverse direction? |
Transcribed Image Text:The free energy change for the following reaction at 25 °C, when [H] = 8.48x103 M and [Fe³+] = 1.12 M, is 161 kj: 2.00H*(8.48×10-3 M) + 2Fe2+ (aq)H₂(g) + 2Fe³+ (1.12 M) AG=161 kj What is the cell potential for the reaction as written under these conditions? Answer: Would this reaction be spontaneous in the forward or the reverse direction? |
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