TReferences The molecular ion in the mass spectrum of 3-methyl-2-pentene appears at m/z 84. Propose a structural formula for the prominent peak at m/z 29. • You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. • In cases where there is more than one answer, just draw one. • Do not use the square brackets tool in your answer. opy aste

TReferences The molecular ion in the mass spectrum of 3-methyl-2-pentene appears at m/z 84. Propose a structural formula for the prominent peak at m/z 29. • You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. • In cases where there is more than one answer, just draw one. • Do not use the square brackets tool in your answer. opy aste

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Select the compound that would show a larger than usual M + 2 peak. O A. CH3CH2F O B. CH3CH2CH2| OC. CH3CH2OH O D.CH3CH2CI
Assign molecules B, C, D and F to the correct mass spectrum and provide the structure of thebase peak. draw the assigned molecules
After submitting a sample for mass spectral analysis you are given the following spectrum: 100 80 - 60 40 20 – 10 20 30 40 50 60 70 80 m/z You know that your sample is either 3-pentanone or 3-pentanol. OH 3-pentanone 3-pentanol Part A: How could you use the mass spectrum above as your only means to determine if your sample is either 3-pentanone or 3- pentanol? Note that the spectrum above lacks a molecular ion. Part B: What is the identity of the sample which provided you with spectrum above: 3-pentanone or 3-pentanol? Relative Intensity
7) Chemical Formula: C₂H₁N IR: weak peak at 3400cm-1 7 1H SH 2H 8) Chemical Formula: C8H1204 IR: strong peak 1720cm-1, peak at 1650cm-1 Unknowns for 1H NMR Final Report 9) Chemical Formula: C5H1002 IR: strong peak at 1750cm-1 1H (8~27 = 16-+2 = € /2=2. PPM 4H 2H 3 PPM 3H 3H 2 * H - (8x2) = 16-12=412=2 -G-H H h+1= 2 4 6H 6H
Which of the following structures corresponds to the mass spectrum shown below? Relative Intensity 100 80- 60 40 20 MS-NW-0358 0-mt 20 40 CI 60 80 100 120 m/z 140 160 180 M+ = 216 200 220
The mass spectrum for acetophenone is shown below. a) Where does the molecular ion show up? ?) b) Which peak is the base peak? ? 1) The mass spectrum for acetophenone is shown below. Relative Intensity 100- 80- 20- acetophenone 0-tyttim 20 10 30 40 50 60 77 trommlilily 70 m/z 80 90 100 105 Ć 110 120 120 a) Where does the molecular ion show up? (m/z = ?) b) Which peak is the base peak? (m/z = ?) c) Draw the structure of the charged species responsible for the peak at m/z = 120. d) Draw the structure of the charged species responsible for the peak at m/z = 105. e) Draw the structure of the charged species responsible for the peak at m/z = 77.
1. What do you suppose is the molecular weight of the molecule that gives the mass spectrum below? 27 Hai 55 26 45 30 40 50 Rel Abund 100r 80- 60- 40- 20- 0- m/z0 10 Rel Abund = Relative Abundance Formula 1: 20 Formula 2: Formula 3: m/z = mass divided by charge 3. What is the base peak? 2. Provide three different molecular formulas (organic molecules, please) that are possible for a molecule with the molecular weight you have chosen. What are the degrees of unsaturation (SODAR) for each? Degrees of unsaturation: Degrees of unsaturation: Degrees of unsaturation: 60 4. Draw a possible molecule for each formula. based on Formula 1 5. Which structure do you think is correct? 72 70 based on Formula 2 80 What mass is lost from the molecular ion to get to the base peak? 90 100 based on Formula 3
4. Draw a possible molecule for each formula. based on Formula 1 5. Which structure do you think is correct? based on Formula 2 based on Formula 3
Unknowns for 1H NMR Final Report 10) Chemical Formula: C₁₂H1s (hard to see but, all peaks that integrate to 1H are doublet of doublets) IR: peak at 1650cm-1 2H 10 2H 1H u 7 1H 11) Chemical Formula: C₁0H12O2 IR: strong peak 1720cm-¹ 6 1H 1H 1H 8 12) Chemical Formula: C₂H₂00 IR: strong broad 3300cm-1 5 2H 2H 1H 3 4 PPM 6 PPM -3 septet 1H PPM 9H 6H 18H 0