tory Bookmarks Profiles Tab Window Help Q Solvely - Take a Picture Math x WeBWorK: MATH 107 online x x Solvely - Take a Picture Math how to screen shot on mac- x + New /webwork2/MATH_107_online_Spring_2024/HW_19_Exponential_Models/2/ Previous Problem Problem List Next Problem In July 2004, the internet was linked by a global network of about 352 million host computers. Assume the number of host computers has been growing approximately exponentially and was about 35.9 million in July 1997. We will find a function N(t) that gives the number of internet host computers (in millions of computers), where t is the number of years after July 1997. We will assume that N(t) is an exponential model with the natural base. In other words, N(t)=-yo-e Use this to complete the following. (a) Translate the information given in the first paragraph above into two data points for the function N(t). List the point that corresponds with 1997 first. NO N7 35.9 352 (b) Next, we will find the two missing parameters for N(t). First, 30 35.9 Then, using the second point from part (a), solve for k. Round to 4 decimal places. k=3261 Note: make sure you have k accurate to 4 decimal places before proceeding. Use this rounded value for k for all the remaining steps. (c) Write the function N(t). N(t) 35.9 0.3261 (d) Based on the answers to parts (b) and (c) above, we may conclude that the number of internet host computers has been growing since 1997 with a continuous percentage growth rate of 32.61 %. (e) What is the doubling time of N? In other words, solve for the value of t where the number of host computers will be double what it was in 1997. Round your answer to 3 decimal places. According to our model, the amount of time that it will take for the number of host computers to double is 2.128 years. (f) According to our model, number of internet host computers in 2012 was about 1022.1 million computers (round to 1 decimal place). (g) We can also express this model in another equivalent form. In particular, we could find b such that N(t)=30 (b). Using the same yo as above, we find that b 1.386 (round to 3 decimal places). #3 80 F3 4 54 a F4 01 85 MacBook Air 65 F5 F6 96 7 87 & 8 F7 * 8 DII 4 F8 F9 F10 61 9 0