took 1217 J to raise the temperature of a sample of water from 12.7 °C to 27.5 °C. onvert 1217 J to calories. 217 J = cal

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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**Energy Conversion Exercise**

**Problem Statement:**

It took 1217 J (joules) to raise the temperature of a sample of water from 12.7 °C to 27.5 °C. 

**Task:**

Convert 1217 J to calories.

**Conversion Formula:**

1 calorie = 4.184 joules

**Calculation:**

To convert joules to calories, divide the energy amount in joules by the conversion factor (4.184 J per cal).

\[ \text{1217 J} = \frac{\text{1217}}{4.184} \, \text{cal} \]

Calculate the result to find out how many calories are equivalent to 1217 J.

**Answer:**

1217 J = ________ cal

Use this space to perform your calculation and record the result.
Transcribed Image Text:**Energy Conversion Exercise** **Problem Statement:** It took 1217 J (joules) to raise the temperature of a sample of water from 12.7 °C to 27.5 °C. **Task:** Convert 1217 J to calories. **Conversion Formula:** 1 calorie = 4.184 joules **Calculation:** To convert joules to calories, divide the energy amount in joules by the conversion factor (4.184 J per cal). \[ \text{1217 J} = \frac{\text{1217}}{4.184} \, \text{cal} \] Calculate the result to find out how many calories are equivalent to 1217 J. **Answer:** 1217 J = ________ cal Use this space to perform your calculation and record the result.
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