**Question:**Tom was running with his uncle. They both started from rest and ran with a constant positive acceleration the entire time. Both Tom and his uncle had the same acceleration. Tom's uncle stopped at time \( t \) while Tom was still running. Tom ran until time \( 4t \) and then he stopped. Compared with his uncle, Tom ran a distance:- ○ eight times as far- ○ four times as far- ○ sixteen times as far- ○ twice as far- ○ 1.4 times as far**Explanation:**This problem involves kinematics with constant acceleration. Tom and his uncle start from rest, meaning their initial velocities are zero. They both have the same constant acceleration.The distance covered under constant acceleration is given by the formula:\[ s = \frac{1}{2} a t^2 \]- For Tom's uncle, who stops at time \( t \): \[ s_{\text{uncle}} = \frac{1}{2} a t^2 \]- For Tom, who runs until time \( 4t \): \[ s_{\text{Tom}} = \frac{1}{2} a (4t)^2 = \frac{1}{2} a \times 16t^2 = 8 a t^2 \]Therefore, Tom runs 8 times the distance his uncle ran. **Answer:**- ○ eight times as far

Name: **Question:**Tom was running with his uncle. They both started from r
Uploaded: 2024-03-05T11:56:34.000Z
Channel: Bartleby
Description: **Question:**Tom was running with his uncle. They both started from rest and ran with a constant positive acceleration the entire time. Both Tom and his uncle had the same acceleration. Tom's uncle stopped at time \( t \) while Tom was still running