A cheetah uses a non-constant acceleration to go from 10 m/s to 25 m/s after 5 seconds. Choose all the following statements that are correct. Than The average acceleration is 3 m/s2. We have enough information to find the distance traveled during this 5 seconds. You can't determine the average acceleration because acceleration is not constant. We have enough information to find the average velocity.
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A cheetah uses a non-constant acceleration to go from 10 m/s to 25 m/s after 5 seconds. Choose all the following statements that are correct.
Than The average acceleration is 3 m/s2.
We have enough information to find the distance traveled during this 5 seconds.
You can't determine the average acceleration because acceleration is not constant.
We have enough information to find the average velocity.
Given values,
Initial velocity,
Final velocity,
time,
Step by step
Solved in 6 steps
- A vehicle accelerates down an on ramp and eventually reaches highway speed. The position of the vehicle is described by the following equation:x(t) = At2/(t+B) a)Write an expression for the vehicle’s instantaneous velocity as a function of time. b)What is the vehicle’s velocity after accelerating for 7 seconds? The equation’s parameters are as follows. A = 35 m/s B = 23 s c)After accelerating, the velocity of the vehicle will begin to level off at highway speed. Write an expression for the vehicle’s velocity after it has been accelerating for a long time. d) Determine the value of the vehicle’s velocity after it has been accelerating for a long time. The equation’s parameters are as follows. A = 35 m/s B = 23 sA football quarterback runs 11.5 m straight down the playing field in 2.42 s. He is then hit and pushed 2.75 m straight backward in 1.64 s. He breaks the tackle and runs straight forward another 23.1 m in 5.54 s. We assume the forward direction to be positive, and the backward position to be negative. Calculate his average velocity in m/s a. for each of the three intervals; b. for the entire motion. Hint a. His average velocities for each of the three intervals are o first interval v₁ = m/s Enter an integer or decimal number [more..] m/s o second interval v₂ = m/s othird interval v3 = b. His average velocity for the entire motion is v = m/sThis is the velocity vs time graph. I would like to see how the position vs time graph will look like.
- You have already traveled 30 miles east and then 30 miles north. To get back to the start, you travel 30 miles west in 1 hour and then 30 miles south in a half hour. What are your average speed and average velocity for the whole rally? Explain your answer.Basam is standing on the edge of a cliff and tosses her physics book upward with a speed of 22.0 m/s. It hits the ground at the base of the cliff 6.0 s later. Create a VELOCITY-TIME graph that represents this scenario. You may assume that the acceleration of the textbook is -9.81 m/s². Use the graph to determine a) the height of the cliff. b) the speed of the book when it impacts the ground. DO NOT use kinematics formulas to solve this problem. This task is assessing your understanding of GRAPHING to represent accelerate motion.A particle moves along the x axis beginning at x = −2 m at time zero. The particle moves forward at speed 4 m/s for 3 seconds, then backward at 3 m/s for 2 seconds, then forward again at 1 m/s for 3 seconds. Draw a position vs. time graph for this motion. Draw a velocity vs. time graph for the same motion.
- A. Calculate the average acceleration for the first ten seconds B. Calculate the average acceleration for the entire trip C. On what intervals of time is the particle moving to the right, moving to the left, a temporary at rest ? D. On what intervals of time is the particle moving with a constant velocity increasing velocity and decelerating calculate its instantaneous acceleration at t=2s Graph given is x: time. Y: velocityThe distance from poplar bluff to Columbia is approximately 250 miles. If you take 4 hours to drive from poplar bluff to Columbia what is your average speed? If you take 6 hours to return from Columbia to poplar bluff what is your average speed? What is the average speed of the whole trip?Salem, Sabrina’s magical black cat, gets scared and jumps straight upward with an initial velocity of 20 m/s from a height of 115-meters.Draw a velocity vs time graph to describe the cat’s motion for the first five seconds of motion.What is the cat’s velocity and acceleration at it’s maximum height?What is the cat’s velocity when it hits the ground?How long does it take for the cat to hit the ground?
- Problem 1: How high can you jump? To model jumping we will split the motion into two parts. For the first part, you crouch and make a displacement up by pushing your feet against the ground. The second part is after your feet leave the ground. For the first part, assume that you create an acceleration of 20.4 m/s 2 while your feet are in contact with the ground and that you make a displacement of 0.2 m. 1. What is your velocity when your feet leave the ground? 2. After your feet leave the ground, what kind of motion do you follow, constant acceleration or constant velocity? State the velocity or acceleration. 3. What is your velocity at your maximum height? 4. Determine how high you go after your feet leave the ground.A van travels a distance d=28 m in the positive x-direction in a time of t=19.5 s. The van immediately brakes and comes to rest in t2=6 s. What are the van's average velocity in the horizontal direction, in meters per second, during t1? What was the acceleration, in meters per second squared, during time interval t1, assuming the van started from rest and moved with a constant acceleration? What was the van's instanteous velocity in the horizontal direction, in meters per second, when it began braking? Using the result from part (c), what was the van's horizontal component of acceleration, in meters persocod squared, during the braking period?Suppose a rock is launched from the ground straight upward (use up as the positive direction) and reaches its maximum height in a time of 3.0 s. Then the rock descends back to the ground. (To simplify your numbers, you may use |g| = 10 m/s².) Find the following: a. The maximum height reached above the ground. b. The velocity of the rock at the time t = 4.5 s.