Tom was running with his uncle. They both started from rest and ran with a constant positive acceleration the entire time. Both Tom and his uncle had the same acceleration. Tom's uncle stopped at time 2t while Tom was still running. Tom ran until time 4t and then he stopped. Compared with his uncle, Tom ran a distance: one-half as far OTwice as far O 1.4 times as far O four times as far O five times as far

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### Physics Problem: Comparing Distances under Constant Acceleration

Tom was running with his uncle. They both started from rest and ran with a constant positive acceleration the entire time. Both Tom and his uncle had the same acceleration. Tom’s uncle stopped at time 2t while Tom was still running. Tom ran until time 4t and then he stopped. 

Compared with his uncle, Tom ran a distance:

- ○ one-half as far
- ○ Twice as far
- ○ 1.4 times as far
- ○ four times as far
- ○ five times as far

### Explanation:
The key concept to solve this problem involves understanding the relationship between time, acceleration, and distance traveled. For an object starting from rest and moving with constant acceleration, the distance \( s \) it travels is given by the formula:

\[ s = \frac{1}{2} a t^2 \]

Where \( a \) is the acceleration and \( t \) is the time.

- **For Tom’s uncle**: He stopped at time \( 2t \), so the distance he traveled is:
  \[ s_{\text{uncle}} = \frac{1}{2} a (2t)^2 = 2a t^2 \]

- **For Tom**: He ran until time \( 4t \), so the distance he traveled is:
  \[ s_{\text{Tom}} = \frac{1}{2} a (4t)^2 = 8a t^2 \]

Therefore, compared with his uncle, Tom ran:
\[ \text{Distance ratio} = \frac{s_{\text{Tom}}}{s_{\text{uncle}}} = \frac{8a t^2}{2a t^2} = 4 \]

Tom ran four times as far as his uncle.
Transcribed Image Text:### Physics Problem: Comparing Distances under Constant Acceleration Tom was running with his uncle. They both started from rest and ran with a constant positive acceleration the entire time. Both Tom and his uncle had the same acceleration. Tom’s uncle stopped at time 2t while Tom was still running. Tom ran until time 4t and then he stopped. Compared with his uncle, Tom ran a distance: - ○ one-half as far - ○ Twice as far - ○ 1.4 times as far - ○ four times as far - ○ five times as far ### Explanation: The key concept to solve this problem involves understanding the relationship between time, acceleration, and distance traveled. For an object starting from rest and moving with constant acceleration, the distance \( s \) it travels is given by the formula: \[ s = \frac{1}{2} a t^2 \] Where \( a \) is the acceleration and \( t \) is the time. - **For Tom’s uncle**: He stopped at time \( 2t \), so the distance he traveled is: \[ s_{\text{uncle}} = \frac{1}{2} a (2t)^2 = 2a t^2 \] - **For Tom**: He ran until time \( 4t \), so the distance he traveled is: \[ s_{\text{Tom}} = \frac{1}{2} a (4t)^2 = 8a t^2 \] Therefore, compared with his uncle, Tom ran: \[ \text{Distance ratio} = \frac{s_{\text{Tom}}}{s_{\text{uncle}}} = \frac{8a t^2}{2a t^2} = 4 \] Tom ran four times as far as his uncle.
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