To test whether the mean time needed to mix a batch of material is the same for machines produced by three manufacturers, Acti-Chem SA (Pty) Ltd obtained the below dataon the time (in minutes) needed to mix the material. Use the data, and summarized information, to test whether the population mean times for mixing a batch of materialdiffer for the three manufacturers. Use a=0.05. Manufacturer 1 (20; 26; 24; 22). Manufacturer 2 (28; 26; 31; 27). Manufacturer 3 (20; 19; 23; 22). Furthermore, the following sumsof squares are given: SST = 104; SSE = 44 and TSS = 148. What is the critical value (rounded off to two decimals)?O A. 4.01O B. 4.90O C. 4.67O D. 4.26

We have to determine the critical value for testing whether the population mean times for mixing a…

Answered: To test whether the mean time needed to…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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What is the Fratio for these data?
A random sample of 50 plants was selected from a field containing one-year-old plants of a variety of guayule, a plant species yielding rubber. Of the 50, 25 were classified as Normal (N), 14 were classified as Off-type (O) and 11 as Aberrant (A). The data on the following page show the percentage rubber content from each plant. Normal Off-type Aberrant 6.34 6.40 5.70 4.84 5.01 6.20 4.25 8.90 6.93 6.38 6.68 7.10 6.42 7.26 7.29 6.30 7.01 6-84 7.12 6.83 7.31 7.25 6.86 6.68 5.82 4.46 7.70 5.90 5.24 5.58 6.36 7.10 6.81 7.32 6.48 5.88 5.24 5.51 7.00 6.42 6.20 6.04 5.58 4.72 7.42 7-27 6.43 6-10 6-01 7.90 (a) Test the null hypothesis that there is no difference in mean rubber content between the three types of plant. (b) If the means of the distributions of each type of plant are denoted by N, PO and PA respectively, test the following particular null hypotheses: (i) EN = RA; (ii) Po=(PN + PA).
Give me a summary of how I should analyze my likert scale data
Refer to the data presented in Exercise 2.86. Note that there were 50% more accidents in the 25 to less than 30 age group than in the 20 to less than 25 age group. Does this suggest that the older group of drivers in this city is more accident- prone than the younger group? What other explanation might account for the difference in accident rates?
The trend of thinner beauty pageant winners has generated charges that the contest encourages unhealthy diet habits among young women. Listed below are body mass indexes (BMI) for beauty pageant winners from two different time periods. Find the coefficient of variation for each of the two sets of data, then compare the variation. The coefficient of variation for the BMI's of beauty pageant winners from the 1920s and 1930s is %
researchers wanted to determine if carpeted rooms contained more baterica than uncapted rooms. to determine the amount of bacterica in a room reseachers pumpled the air from the room over a petri dish at the rate of 1 cubic foot per minute for eight carpeted rooms and eight uncaprted rooms. colonies of baterica were alled to form in 16 petri dishes. the results shown below are the baterica counta per cubic foot mean standard deviation sample size capeted room 11.2 2.6774 8 uncapted room 9.7875 3.21 8 you want ti test using sigificance level of 0.01 whether the mean bactiria count is high for carpeted rooms than for uncapteed rooms. test whether the mean bacteria count is high for carpeted rooms thatn uncarpeted rooms. show all steps using the p value method. what is Ho and H1? what is the test statsic and p value? what conclusion can be made?
Ride services are on the rise, such as Uber and Lyft. You wondered if the recent news reports of crime occurring with these ride services impacted the usage of them, especially with women. You decide to conduct a survey about ride service usage among male and female college students. The results showed that 19 males use ride services and 11 do not. While 12 females use ride services and 18 do not. Calculate the chi-square statistic:
Las Vegas has seen increased competition from Singapore and Macau for customers in the casino resort industry. One measurement of success is the average length of stay by visitors. The data in this file show the number of days a random sample of visitors stayed at each location. a. Using α = 0.05 to determine if there is a difference in the average length of stay by visitors for the three locations. Follow the steps as outlined in the exercises. b. If warranted, perform a multiple comparison test to determine which pairs are different using α = 0.05. c. Verify your results using Excel.
On average, a sample of n = 36 scores will provide a better estimate of the population mean than a sample of n = 49 scores from the same population.
An outbreak of the deadly Ebola virus in 2002 and 2003 killed 91 of the 95 gorillas in 7 home ranges in the Congo. To study the spread of the virus, measure " distance" by the number of home ranges separating a group of gorillas from the first group infected. Here are data on distance and number of days until deaths began in each later group: Distance xx 2 5 4 4 4 6 Days yy 4 21 29 40 47 49 Use a calculator or software to find the following values. (a) Find the mean and standard deviation of xx. MEAN: STANDARD DEVIATION: (b) Find the mean and standard deviation of yy. MEAN: STANDARD DEVIATION: (c) Find the correlation rr between xx and yy. r:
With Scheffe's S Test, perform the pairwise comparisons of the means and summarize the result of comparisons. Below are the data:
The chlorine added to swimming pools to combat relatively short shelf before it loses its effectiveness. Records indicate that the mean shelf life of a 5 gallon jug of chlorine is 2,160 hours (90 days). As an experiment, Holdlonger was added to the chlorine to whether it would increase the shelf life of the chlorine. A sample of nine jugs of chlorine had these shelve lives (in hours): 2,159, 2, 170, 2,180, 2,179, 2,160, 2,167, 2,171, 2,181 and 2,185. At the .025 significance level, has Holdlonger increased the shelf life of the chlorine? S=9.3823, sample mean=2172.44 STATE THE NULL AND ALTERNATE HYPOTHESIS. Determine the critical value for the decision rule.

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