To sterilize a 20.0-g glass baby bottle, we must raise its temperature from 17.0°C to 95.0°C. How much heat transfer is required? The specific heat of glass is 840 J/(kg · °C).

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**Heat Transfer Calculation for Glass Baby Bottle Sterilization**

*Welcome to our educational section on heat transfer calculations! In this example, we will calculate the amount of heat needed to sterilize a glass baby bottle.*

*Problem Statement:*

To sterilize a 20.0-g glass baby bottle, we must raise its temperature from 17.0°C to 95.0°C. How much heat transfer is required? The specific heat of glass is 840 J/(kg・°C).

*Given Data:*
- Mass of the glass baby bottle (m): 20.0 g = 0.020 kg
- Initial temperature (T₁): 17.0°C
- Final temperature (T₂): 95.0°C
- Specific heat capacity of glass (c): 840 J/(kg・°C)

*Formula:*
The heat energy (Q) required to raise the temperature can be calculated using the formula:
\[ Q = m \cdot c \cdot \Delta T \]
where:
- \( \Delta T \) = T₂ - T₁ = 95.0°C - 17.0°C = 78.0°C

*Calculation:*
\[ Q = 0.020 \, \text{kg} \times 840 \, \frac{\text{J}}{\text{kg} \cdot ^\circ \text{C}} \times 78.0 \, ^\circ \text{C} = 1310.4 \, \text{J} \]

The amount of heat transfer required to sterilize the glass baby bottle is **1310.4 J**.
Transcribed Image Text:**Heat Transfer Calculation for Glass Baby Bottle Sterilization** *Welcome to our educational section on heat transfer calculations! In this example, we will calculate the amount of heat needed to sterilize a glass baby bottle.* *Problem Statement:* To sterilize a 20.0-g glass baby bottle, we must raise its temperature from 17.0°C to 95.0°C. How much heat transfer is required? The specific heat of glass is 840 J/(kg・°C). *Given Data:* - Mass of the glass baby bottle (m): 20.0 g = 0.020 kg - Initial temperature (T₁): 17.0°C - Final temperature (T₂): 95.0°C - Specific heat capacity of glass (c): 840 J/(kg・°C) *Formula:* The heat energy (Q) required to raise the temperature can be calculated using the formula: \[ Q = m \cdot c \cdot \Delta T \] where: - \( \Delta T \) = T₂ - T₁ = 95.0°C - 17.0°C = 78.0°C *Calculation:* \[ Q = 0.020 \, \text{kg} \times 840 \, \frac{\text{J}}{\text{kg} \cdot ^\circ \text{C}} \times 78.0 \, ^\circ \text{C} = 1310.4 \, \text{J} \] The amount of heat transfer required to sterilize the glass baby bottle is **1310.4 J**.
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