You wish to cool a 1.59 kg block of tin initially at 96.0°C to a temperature of 57.0°C by placing it in a container of kerosene initially at 28.0°C. Determine the volume (in L) of the liquid needed in order to accomplish this task without boiling. The density and specific heat of kerosene are respectively 820 kg/m³ and 2,010 J/(kg °C), and the specific heat of tin is 218 J/(kg °C). L Need Help? Read It
You wish to cool a 1.59 kg block of tin initially at 96.0°C to a temperature of 57.0°C by placing it in a container of kerosene initially at 28.0°C. Determine the volume (in L) of the liquid needed in order to accomplish this task without boiling. The density and specific heat of kerosene are respectively 820 kg/m³ and 2,010 J/(kg °C), and the specific heat of tin is 218 J/(kg °C). L Need Help? Read It
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:You wish to cool a 1.59 kg block of tin initially at 96.0°C to a temperature of 57.0°C by placing it in a container of kerosene
initially at 28.0°C. Determine the volume (in L) of the liquid needed in order to accomplish this task without boiling. The density
and specific heat of kerosene are respectively 820 kg/m³ and 2,010 J/(kg °C), and the specific heat of tin is 218 J/(kg °C).
L
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Expert Solution
Given data
Given data :
Mass of tin ( m1 ) = 1.59 kg
Initial temperature of tin ( T1 ) = 96.0 °C
Final temperature ( T ) = 57.0 °C
Initial temperature of kerosene ( T2 ) = 28.0 °C
Density of kerosene ( ρ ) = 820 kg/m3
Specific heat capacity of kerosene ( c2 ) = 2010 J/(kg.°C)
Specific heat capacity of tin ( c1 ) = 218 J/(kg.°C)
To find :
Let mass of kerosene is m2
Volume of kerosene is V
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