To solve a quadratic equation using the quadratic formula: 1. Write down the values for a, b, and c. 2. Plug in the values for a, b, and c into the formula: x= -b+√b²-4ac 2a 3. Simplify the expression under the radical. в с Practice: Solve the equations below using the quadratic formula. 5. 27²-2 4.-x²-2x+13=0 5. 2x² - 2x -15=0 Ac-x² B = -2x C = 13 x = -2x+1=2x² -4 (-2x) (13) = I1 4-41-21(13) 4 6.4x²-7= 0 A-4x² B=0 C=-7 x=2x² B = -2₁ C= -15 A 7.3x² - 2x-5=0 A=3x² 13 =-2x (= -5

Q: 4- -> 이 -4 4 -2 2. 6 2.

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A: We have to solve above Quadratic equations

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A: Length is scalar quantity

Q: 10. x2 - 14x + c 12. x2 + 5x + c 14. x2 - x + c

A: 10) the complete square will be (x-7)^2 12) the complete square will be (x+5/2)^2

Q: Solve each equation by extracting square roots.a. 4x2 = 12b. (x − 3)2 = 7

A: Given: Part a: 4x2=12 Now taking square root on both sides we get, 4x2=±12⇒2x=±23x=±3

Q: Solve the equation by taking the square root. 6x -11=-215 O There is no correct answer given. OS 113…

A: Given: 6x2-11=-215

Q: 4-3x² = -77 (x + 2)² = 49 20. 5x2 + 10 = 310 23. 3(x-1)² = 18

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Q: Solve the equation by taking the square root. -6-12n -396 O {i/33,-1/33} O {7-5, –7-/6} O {14,-14} O…

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Q: Determine the present value P that must be invested to have the future value A at simple interest…

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