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Solve the quadratic equation by completing the square. x² +11x-5=0 Choose the appropriate process for rearranging the equation, if needed, before completing the square to obtain an equation of the form (x + k)² = d. (Type an integer or a simplified fraction.) OA. x² +11x-5-0⇒x² +11x=5 ⇒ x² + 11x + = 5 OB. x² +11x-5=0⇒x² +11x=5 ⇒ x² + 11x + = 5+ 1 5 2 Oc. x² +11x-5=0⇒x² +11x=5 ⇒ x² + x + 11 11 1 5 2 OD. x² +11x-5-=0⇒x² +11x=5 ⇒ +X+ 11 11 4

Solve the quadratic equation by completing the square. x² +11x-5=0 Choose the appropriate process for rearranging the equation, if needed, before completing the square to obtain an equation of the form (x + k)² = d. (Type an integer or a simplified fraction.) OA. x² +11x-5-0⇒x² +11x=5 ⇒ x² + 11x + = 5 OB. x² +11x-5=0⇒x² +11x=5 ⇒ x² + 11x + = 5+ 1 5 2 Oc. x² +11x-5=0⇒x² +11x=5 ⇒ x² + x + 11 11 1 5 2 OD. x² +11x-5-=0⇒x² +11x=5 ⇒ +X+ 11 11 4

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Solve the quadratic equation by completing the square. x² +11x-5=0 Choose the appropriate process for rearranging the equation, if needed, before completing the square to obtain an equation of the form (x + k)² = d. (Type an integer or a simplified fraction.) OA. x² +11x-5-0⇒x² +11x=5 ⇒ x² + 11x + = 5 OB. x² +11x-5=0⇒x² +11x=5 ⇒ x² + 11x + = 5+ 1 5 2 OC. x² +11x-5-0⇒x² +11x=5 ⇒ x² + x + 11 11 1 5 2 OD. x² +11x-5-0⇒x² +11x=5 ⇒ +X+ 11 11 4
Transcribed Image Text:Solve the quadratic equation by completing the square. x² +11x-5=0 Choose the appropriate process for rearranging the equation, if needed, before completing the square to obtain an equation of the form (x + k)² = d. (Type an integer or a simplified fraction.) OA. x² +11x-5-0⇒x² +11x=5 ⇒ x² + 11x + = 5 OB. x² +11x-5=0⇒x² +11x=5 ⇒ x² + 11x + = 5+ 1 5 2 OC. x² +11x-5-0⇒x² +11x=5 ⇒ x² + x + 11 11 1 5 2 OD. x² +11x-5-0⇒x² +11x=5 ⇒ +X+ 11 11 4
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