← The area of a rectangular wall of a bam is 32 square feet. Its length is 4 feet longer than the width. Find the length and width of the wall of the bam. The width is feet.
← The area of a rectangular wall of a bam is 32 square feet. Its length is 4 feet longer than the width. Find the length and width of the wall of the bam. The width is feet.
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
Related questions
Question

Transcribed Image Text:←
The area of a rectangular wall of a bam is 32 square feet. Its length is 4 feet longer than the width. Find the length and width of the wall of the
bam.
The width is feet.
(...)

Transcribed Image Text:Solve the equation by completing the square.
X-7x+6=0
Choose the appropriate process for rearranging the equation, if needed, before completing the square to obtain an equation of the form
(x + k)² = d.
(Type an integer or a simplified fraction.)
OA. x²-7x+6=0⇒x²-7x= -6 ⇒x² - 7x +
= -
= -6
OB. x²-7x+6=0⇒x² - 7x=
x = -6 ⇒ = x²-x +
=
6
7
12
OC. x² - 7x+6=0⇒x² - 7x = -6x²-x+=+
O D. x² - 7x+6=0⇒x² - 7x = -6 ⇒x² - 7x + = -6+
▸
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